Answer:
#3: 81
Step-by-step explanation:
I haven't done this type of math in a while so I'm unsure about #1 and #2, but #3 is 81.
3^4 = 3 × 3 × 3 × 3
3^4 = 9 × 3 × 3
3^4 = 27 × 3
3^4 = 81
13.2 gallons hope this helped!
Answer:
43.6 amp
Step-by-step explanation:
Given
A 40 amp fuse carries a temporary 9 % current overload.
9% current overload means that whatever will be the normal current carrying capacity of fuse, during overload it carries 9% more than that.
Current carrying capacity of fuse is 40 amp.
during overload it carries 9% more
over load current = 9% of 40 amp = 9/100 *40 = 3.6 amp
total current flowing through fuse during overload = 40 amp + 3.6 amp
= 43.6 amp (answer)
Answer:
22. The surface area is 1/9 of its original value
24. The surface area is 120 m^2 less than its original value.
Step-by-step explanation:
22. For similar figures, the surface area is proportional to the square of the linear dimension scale factor. Multiplying all linear dimensions by 1/3 will result in reducing the surface area to (1/3)^2 = 1/9 of its original value.
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24. As above, the scaled base surface area will be (1/4)^2 = 1/16 of its original value. Since one dimension of the lateral area is multiplied by 4 and the other dimension is multiplied by 1/4, the net effect on that area is multiplication by (1/4)(4) = 1. That is, the lateral area will remain unchanged.
The overall surface area will be reduced by 15/16 of the area of the bases. The area of the bases is (2)(1/2)(8 m)(16 m) = 128 m^2. The changed figure will have a surface area that is 120 m^2 smaller.
Domain is all the values that go into a function, and the range is all the values that come out.