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3 years ago

Solve the Equation. 14x+28=14

Mathematics

1 answer:

Korvikt [17]3 years ago

8 0

Answer:

x= -1

Step-by-step explanation:

1. First, you need to combine like terms. Constants with constants and variables with variables. Since there is only one variable, there is nothing to combine it with so nothing happens to it. The constants, on the other hand, can combine.

2. You have to subtract 28 from 28 and 14 so that +28 can cancel out on the left side and combine on the right.

3. That will leave you with 14x= -14.

4. Now you need to get x on its own so you need to divide 14 (opposite of multiplication to cancel out) on both sides.

5. That will leave you with x= -1. That is your final answer.

Hope this helps! Please vote me as Brainliest. Let me know if you need more of an explanation. Remember, cheating is never the answer. Try your best before you seek answers. Hope it's not too late. Good luck with whatever you are doing! Have an amazing day!

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What is the value of -3/2÷-7/2?

wlad13 [49]

The value of the given division operation is 3/7

<h3>Division operation</h3>

From the question, we are to determine the quotient of the given division operation

The given division operation is

-3/2÷-7/2

$\frac{-3}{2} \div \frac{-7}{2}$

$=\frac{-3}{2} \times \frac{2}{-7}$

$=\frac{-3}{-7}$

$=\frac{3}{7}$

Hence, the value of the given division operation is 3/7

Learn more on Division operation here: brainly.com/question/27903912

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8 0

2 years ago

111 = 14a This part is for the extra characters

Tamiku [17]

I think it's the answer

7 0

3 years ago

Every year a man is paid $500 more than the previous year. If he receives $17,800 over four years, what was he paid in the first

iragen [17]

Let x+500 represent the first year

For the $500 more than the previous year for 4 years, we would write:
(x+500)+(x+500+500+500)+(x+500+500+500+500)= 17,800

By adding the equation above, 4x+5000=17,800

4x=17,800-5000
4x=12,800
x=3,200

So the amount the man was paid in the first year is 3,200+500=3,700

8 0

3 years ago

Read 2 more answers

Suppose that theta is an angle in standard position whose terminal side Intersects the unit circle at (-11/61, -60/61)

Blizzard [7]

Answer:

The exact values of the tangent, secant and cosine of angle theta are, respectively:

$\cos \theta = -\frac{11}{61}$

$\tan \theta = \frac{-\frac{60}{61} }{-\frac{11}{61} } = \frac{60}{11}$

$\sec \theta = \frac{1}{-\frac{11}{61} } = -\frac{61}{11}$

Step-by-step explanation:

The components of the unit vector are $x = -\frac{11}{61}$ and $y = -\frac{60}{61}$ . Since $r = 1$ , then $x = \cos \theta$ and $y = \sin \theta$ . By Trigonometry, tangent and secant can be calculated by the following expressions: