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2 years ago

7 divide by k in algebric expression

Mathematics

1 answer:

Salsk061 [2.6K]2 years ago

4 0

7 devide by k in algebric function = 7/k

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In the xy-plane, the graph of function f(x) has zeros at −5, −2, and 2. Write the polynomial function.

Alona [7]

Answer:

$f(x) = x^3 +5x^2-4x-20$

Step-by-step explanation:

Given

$Zeros: -5,-2,2$

Required

The polynomial function

If a function has a, b and c as its zeros, the function is:

$f(x) = (x - a)(x - b)(x - c)$

So, we have:

$Zeros: -5,-2,2$

$f(x) = (x - (-5))(x - (-2))(x - 2)$

Open the inner brackets

$f(x) = (x +5)(x +2)(x - 2)$

Expand the difference of two squares

$f(x) = (x +5)(x^2 - 4)$

Expand

$f(x) = x^3 +5x^2-4x-20$

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2 years ago

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Marina86 [1]

Answer:

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7 0

2 years ago

Write a problem that can be solved by using equal groups

kap26 [50]

5+5
=10
2 groups of 5

8 0

3 years ago

Please answer correctly and no links

victus00 [196]

Answer:

step 3

Step-by-step explanation:

take away 2 add 4 then multiple 9000 then divide 1 then you got your answer 20/56.

8 0

2 years ago

3^2 - 2x + 4 and g(x) = 5x^2 + 6x - 8 find f-g(x)

sveta [45]

Answer:

For the given functions f(x) and g(x) $(f-g)(x) = -2x^{2} - 8x +12$

Step-by-step explanation:

Here, the given function are:

$f(x) = 3x^{2} - 2x+ 4\\g(x) = 5x^{2} + 6x -8$

Now, simplifying for (f-g)(x) = f(x) - g(x):

$f(x) - g(x) = (3x^{2} - 2x+ 4) - (5x^{2} + 6x -8)$

$= 3x^{2} - 2x+ 4- 5x^{2} - 6x +8$

Doing operation on LIKE TERMS, we get

f(x) - g(x) = $( 3x^{2}- 5x^{2}) + (-2x - 6x) +( 4 +8) = -2x^{2} - 8x + 12$

Hence, for the given functions f(x) and g(x) $(f-g)(x) = -2x^{2} - 8x +12$

4 0

3 years ago

7 divide by k in algebric expression​

7 divide by k in algebric expression