7 divide by k in algebric expression

Which of the following are considered measures of center? I. mean II. median III. interquartile range A. III only B. I and II on

andrezito [222]

Answer: Choice B) I and II only

The mean and median are considered measures of center as they represent the average of a data set. The average basically being a point that collectively speaks for all of the data. For example, if you have a group of basketball players whose heights range from 5'11" to 6'9", then there is no single height to report; however, we can compute the average to get a basic idea of the single height. The interquartile range (IQR) is a measure of variability or spread of the data. The higher the IQR, the more spread out the data is. Recall that 50% of the data is represented by the IQR and that IQR = Q3 - Q1 where Q1 and Q3 are the first and third quartiles respectively. So because the IQR is a measure of spread, it is not considered a center point.

4 0

3 years ago

What is the answer to (9/10 - 2/5) - 1/3 and how do u get the answer

Oksanka [162]

$(\frac{9}{10}-\frac{2}{5})-\frac{1}{3}=\ \ \ \ \ | make\ a\ common\ denominator\\\\
(\frac{27}{30}-\frac{12}{30})-\frac{10}{30}=\ \ \ | omit\ the\ bracket\\\\\frac{27}{30}-\frac{12}{30}-\frac{10}{30}=\frac{27-12-10}{30}=\frac{5}{30}=\frac{1}{6}\\\ Solution\ is\ \frac{1}{6}.$

6 0

3 years ago

Consider the function represented by 9x+3y = 12 with x as the independent variable. How can this function be

Delicious77 [7]

Answer:

f(x) = -3x + 4

Step-by-step explanation:

Given function:

9x + 3y = 12

Putting this into slope-intercept form: y = mx + b

9x + 3y = 12
3y = -9x + 12
y = -3x + 4

Replacing y with f(x)

f(x) = -3x + 4

6 0

3 years ago

15. Fatima bought a video game that has a

OleMash [197]

Answer:

Step-by-step explanation:

Discount = 15% of 45

$=\frac{15}{100}*45\\\\=\frac{675}{100}=6.75$

= $6.75

Price of the video game = 45 - 6.75 = $38.25

Tax = 7%of 38.25

$=\frac{7}{100}*38.25\\\\=\frac{267.75}{100}=2.6775$

Price paid by Fatima for the video game = 38.25 + 2.68 = $ 40.93

6 0

3 years ago

3. A new process has been developed for applying pho toresist to 125-mm silicon wafers used in manufac turing integrated circu

dlinn [17]

Answer:

a

The null hypothesis is $H_o : \mu = 13.4000$

The alternative hypothesis is $H_a : \mu \ne 13.4000$

The null hypothesis is rejected

b

The 99% confidence level is $13.3930 < \mu < 13.3994$

Step-by-step explanation:

From the question we are told that

The sample size is n = 10

The population mean is $\mu = 13.4 000 \ angstroms$

The level of significance is $\alpha = 0.05$

The sample data is

13.3987, 13.3957, 13.3902, 13.4015, 13.4001, 13.3918, 13.3965, 13.3925, 13.3946, and 13.4002

Generally the sample mean is mathematically represented as

$\= x = \frac{13.3987+ 13.3957\cdots +13.4002 }{10}$

=> $\= x = 13.3962$

Generally the sample standard deviation is mathematically represented as

$\sigma = \sqrt{\frac{\sum (x_i - \= x)^2}{n} }$

=> $\sigma = \sqrt{\frac{ (13.3987 - 13.3962)^2 + (13.3987 - 13.3962)^2 + \cdots + (13.3987 -13.4002)^2 }{10} }$

=> $\sigma =0.0039$

The null hypothesis is $H_o : \mu = 13.4000$

The alternative hypothesis is $H_a : \mu \ne 13.4000$

Generally the test statistics is mathematically represented as

$z = \frac{\= x - \mu}{\frac{\sigma}{\sqrt{n} } }$

=> $z = \frac{13.3962 - 13.4000}{\frac{0.0039}{\sqrt{10} } }$

=> $z = 3.08$

Generally the p-value is mathematically represented as

$p-value = 2P( z > 3.08)$

From the z-table $P(z > 3.08)= 0.001035$

So

$p-value = 2* 0.001035$

$p-value = 0.00207$

So from the obtained value we see that

$p-value < \alpha$

Hence the null hypothesis is rejected

Consider the b question

Given that the confidence level is 99% then the level of significance is

$\alpha = (100 -99)\%$

=> $\alpha = 0.01$

Generally from the normal distribution table critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 2.58$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma}{\sqrt{n} }$

=> $E = 2.58 * \frac{0.0039}{\sqrt{10} }$

=> $E = 0.00318$

Generally the 99% confidence interval is mathematically represented as

$13.3962 - 0.00318 < \mu < 13.3962 + 0.00318$

=> $13.3930 < \mu < 13.3994$

7 0

3 years ago

7 divide by k in algebric expression​

7 divide by k in algebric expression