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wel
2 years ago
5

PLEASE help will mark branliest!! Find the number of possibilities using combinations. image attached.

Mathematics
1 answer:
seropon [69]2 years ago
5 0

Answer:

121

Step-by-step explanation:

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What is the equivalent fraction to 2/3
Paraphin [41]

Answer:4/6

Step-by-step explanation:because we multiply the fraccion by 2

8 0
3 years ago
How old were the twins who played in the recital?
inna [77]
To find out how old the twins were that were in the recital you need to be able to interpret a stem and leaf plot.  The number of the left gets placed with each number on the right to create a number in the data set.  See the key for an example.  This means there were 2 people that were 5 years old making them the twins!
3 0
3 years ago
Help a sis out please
DedPeter [7]
The answer to this question would be yes
4 0
3 years ago
An urn contains nine red and one blue balls. A second urn contains one red and five blue balls. One ball is removed from each ur
il63 [147K]

Answer:

0.362

Step-by-step explanation:

When drawing randomly from the 1st and 2nd urn, 4 case scenarios may happen:

- Red ball is drawn from the 1st urn with a probability of 9/10, red ball is drawn from the 2st urn with a probability of 1/6. The probability of this case to happen is (9/10)*(1/6) = 9/60 = 3/20 or 0.15. The probability that a ball drawn randomly from the third urn is blue given this scenario is (1 blue + 5 blue)/(8 red + 1 blue + 5 blue) = 6/14 = 3/7.

- Red ball is drawn from the 1st urn with a probability of 9/10, blue ball is drawn from the 2nd urn with a probability of 5/6. The probability of this event to happen is (9/10)*(5/6) = 45/60 = 3/4 or 0.75. The probability that a ball drawn randomly from the third urn is blue given this scenario is (1 blue + 4 blue)/(8 red + 1 blue + 1 red + 4 blue) = 5/14

- Blue ball is drawn from the 1st urn with a probability of 1/10, blue ball is drawn from the 2nd urn with a probability of 5/6. The probability of this event to happen is (1/10)*(5/6) = 5/60 = 1/12. The probability that a ball drawn randomly from the third urn is blue given this scenario is (4 blue)/(9 red + 1 red + 4 blue) = 4/14 = 2/7

- Blue ball is drawn from the 1st urn with a probability of 1/10, red ball is drawn from the 2st urn with a probability of 1/6. The probability of this event to happen is (1/10)*(1/6) = 1/60. The probability that a ball drawn randomly from the third urn is blue given this scenario is (5 blue)/(9 red + 5 blue) = 5/14.

Overall, the total probability that a ball drawn randomly from the third urn is blue is the sum of product of each scenario to happen with their respective given probability

P = 0.15(3/7) + 0.75(5/14) + (1/12)*(2/7) + (1/60)*(5/14) = 0.362

8 0
3 years ago
How do you solve <br> 5x/3 -2 when x = -18
Dennis_Churaev [7]

Answer:

5×-18/3-2

5×-6-2

-30-2

=32 answer

hope it help you

5 0
3 years ago
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