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Free_Kalibri [48]
3 years ago
15

Please help solve for x ................................................................

Mathematics
2 answers:
Ratling [72]3 years ago
3 0

Answer:

104°+33°+(5x+13)°=180°[all angle sum is 180°]

137°+(5x+13)=180°

137°+13+5x=180°

150°+5x=180°

5x=180°-150°

5x=30

x=30/5

×=6

ivolga24 [154]3 years ago
3 0

Answer:

x = 6

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°

Sum the 3 angles and equate to 180

5x + 13 + 104 + 33 = 180, that is

5x + 150 = 180 ( subtract 150 from both sides )

5x = 30 ( divide both sides by 5 )

x = 6

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tankabanditka [31]

Answer:

The option " The sum has degree of 6 , but the difference has a degree of 7 " is correct.

Step-by-step explanation:

Given that the sum and difference of the polynomials 3x^5y-2x^3y^4-7xy^3 and -8x^5y+2x^3y^4+xy^3

<h3>Now sum the given polynomials :</h3>

3x^5y-2x^3y^4-7xy^3+(-8x^5y+2x^3y^4+xy^3)

=3x^5y-2x^3y^4-7xy^3-8x^5y+2x^3y^4+xy^3

=-5x^5y+0-6xy^3

=-5x^5y-6xy^3

Therefore 3x^5y-2x^3y^4-7xy^3+(-8x^5y+2x^3y^4+xy^3)=-5x^5y-6xy^3

In the simplified <u>sum of the polynomials</u> -5x^5y-6xy^3  we have <u>the degree is 6</u>

<h3>Now difference the polynomials </h3>

3x^5y-2x^3y^4-7xy^3-(-8x^5y+2x^3y^4+xy^3)

=3x^5y-2x^3y^4-7xy^3+8x^5y-2x^3y^4-xy^3

=11x^5y-4x^3y^4-8xy^3

Therefore 3x^5y-2x^3y^4-7xy^3-(-8x^5y+2x^3y^4+xy^3)=11x^5y-4x^3y^4-8xy^3

In the simplified <u>difference of polynomials</u> 11x^5y-4x^3y^4-8xy^3 we have <u>the degree is 7</u>

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Given:

Price change of four companies \dfrac{5}{8},-0.25,-\dfrac{1}{8}\text{ and }1.5.

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Answer:

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