L=length, w=width
l=2w+5
2l+2w=34
2l=4w+10 [here I just multiplied the first equation by two]
4w+10+2w=34 [substitute 4w+10 for 2l]
6w=24, w=4
remember l=2w+5 so l=2(4)+5=13
Answer: The length is 13.
Shortest side= x longest side= 2x third side= 10cm+x
58cm=x+2x+10cm+x
58cm=4x+10cm
48cm=4x
12cm=x
shortest side= 12cm longest side= 24cm third side=22cm
I only figured out the answer for the Dorthy question, the answer is 210
Answer:
2196 fish
Step-by-step explanation:
Weight of fish that the killer whale might eat in a month (30 days) = 14,000 lb
Weight of the fish that killer whale might eat in a day =
lb.
Average weight of the fish that killer whale eats = 3.4 oz
Since,
1 pound(lb) = 16 ounces(oz)
So,
Weight of the fish that killer whale might eat in a day in ounces(oz) =
oz
Since, a certain fish weighs 3.4 oz, in order to find the number of fish that killer whale must eat, we must divide the total weight in ounces by 3.4 ounces.
So, the number of fish that killer whale would eat =
fish
Thus, the killer whale needs to eat 2196 fish.