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alex41 [277]
3 years ago
12

A university with remote campuses, which all use different service providers, loses Internet connectivity across all locations.

After a few minutes, Internet and VoIP services are restored, only to go offline again at random intervals, typically within four minutes of services being restored. Outages continue throughout the day, impacting all inbound and outbound connections and services. Services that are limited to the local LAN or WiFi network are not impacted, but all WAN and VoIP services are affected. Later that day, the edge-router manufacturer releases a CVE outlining the ability of an attacker to exploit the SIP protocol handling on devices, leading to resource exhaustion and system reloads. Which of the following BEST describe this type of attack?
A. DOS
B. SSL Stripping
C. Memory leak
D. Race condition
E. Shimming
F. Refactoring
Computers and Technology
1 answer:
Anastaziya [24]3 years ago
5 0

Answer:

A & D.

Explanation:

In real time operating system, the best description for this type of attack explained in the question is;

DOS and Race Condition.

Because race condition takes place when 2 or more threads are able to both access and change shared data simultaneously ,while DOS is a good foundation to build a custom made Real time operating system.

Thus, options A & D are correct.

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Which type of image is not a supported using the Online Pictures or Insert Picture command?
IgorC [24]

Answer:

HTML  i think

Explanation:

4 0
3 years ago
Read 2 more answers
Write the definition of a function typing_speed, that receives two parameters. The first is the number of words that a person ha
Lera25 [3.4K]

Answer:

The definition of function is as follows:

def typing_speed(number_of_words,Time_Interval):

number_of_words>=0  

Time_Interval>0

speed=float(60*number_of_words/Time_Interval)

return speed

Explanation:

Above function is defined step-by-step as follows:

        def typing_speed(number_of_words,Time_Interval):

  • A function named typing speed has two arguments, num_of_words and Time_Interval.

                             number_of_words>=0  

                             Time_Interval>0

  • The variable number_of_words is the number of words entered that a person enters, they must be greater than or equal to 0. Where as Time_Interval is the variable for counting the time span in seconds, it must be greater than 0.

                    speed=float(60*number_of_words/Time_Interval)

                    return speed

  • For determining result firstly the seconds are converted int minutes by multiplying with 60 and number_of_words is divided with Time_Interval in order to get words per minute. The return value will give speed which has data type float.

4 0
3 years ago
Write a program that prompts the user to enter positive integers (as many as the user enters) from standard input and prints out
julia-pushkina [17]

Answer:

Here is the JAVA program that prompts the user to enter positive integers from standard input and prints out the maximum and minimum values:

import java.util.*;

public class Ex0603 {

   public static void main(String[] args) { //start of main function

   Scanner in = new Scanner(System.in); //creates Scanner class object to take input from user

   int minimum = 0; //stores the minimum of the integers

   int maximum = 0; //stores the minimum of the integers

   int num; //stores the positive integer values

   System.out.println("enter a positive integer: ");//prompts user to enter a positive integer

   num = in.nextInt();//scans and reads the input integer value from user

   minimum = num;  //assigns value of num to minimum

   while(true) {//while loop keeps prompting user to enter a positive integer

       System.out.println("enter a positive integer: ");//prompts user to enter a positive integer

       num = in.nextInt();//scans and reads the input integer value from user

       if(num <=0)//if the user inputs a negative integer or 0

           break; //breaks the loop

       if (num > maximum) {//if the value of positive integer is greater than the maximum of value

           maximum = num; } //assigns that maximum value of num to maximum variable

       if (num < minimum) {//if the value of positive integer is less than the minimum of value

           minimum = num; //assigns that minimum value of num to minimum       }    }            

   System.out.println("The maximum integer is : " + maximum); //displays the maximum of the positive integers

   System.out.println("The minimum integer is : " + minimum); }}   //displays the minimum of the positive integers

Explanation:

Here is the JAVA program that that prompts the user to enter an integer N, then reads N double values, and prints their mean (average value) and sample standard deviation:

import java.util.*;  

public class Ex0603 {  

public static void main(String[] args) { //start of main function

Scanner in = new Scanner(System.in);  //creates Scanner class object to take input from user

double integer= 0;  //to store the number of input values

double sum = 0;  //to store the sum of input numbers

double mean = 0;  //to store the average of numbers

double sd = 0;  //to store the standard deviation result

double variance = 0;  //to store the variance result

double sumSquare = 0;  //to store the sum of (num-mean)^2

int n = 0;  //to store the sample size N

   System.out.println("Enter an integer: ");  //prompts user to enter an integer that is how many elements user wants to input

   integer = in.nextInt();  //reads the value of integer from user

   double size=integer; // declares a double type variable and assigns value of int type variable integer to this double type variable size

   int i=0;  //used to point each element of the num array

   double num[] = new double[(int)size];  //declares an array to hold the numbers input by user

   while(integer>0){  //loop executes until value of integer is greater than 0

   System.out.println("Enter a number: "); // prompts to enter a number

   num[i] = in.nextDouble(); //reads double values

   sum += num[i];  //adds the values stored in num array

   i++;  //increments i to point to the next element in num array

   n++;  //increments n to count the total number of elements

  integer--; //decrements integer value at each iteration

   mean = sum / n;    }  //compute the average of values

   i=0;  

    while(size>0){  //loop executes until value of size exceeds 0

       sumSquare += Math.pow(num[i]-mean,2); //takes the sum of square difference between each element of num array and value of mean

       i++; //increments i

      size--;   }  //decrements size

variance = sumSquare / (n-1);  //compute variance by dividing the result of sum of the squares of their differences from the mean by n-1

   sd = Math.sqrt(variance);  //computes standard deviation by using sqrt function which takes the sqrt of the result of variance computed above

System.out.println("Average value is: " + mean+ " and the standard deviation is " + String. format("%.2f", sd));   }} //displays the average of numbers stored in mean variable and value of standard deviation is displayed up to 2 decimal places

Screenshots of both programs and their outputs is attached.

7 0
3 years ago
Complete two examples of how scientists, technologists, engineers, and mathematicians may work together to create a new product
asambeis [7]

Answer:

By thinking of ways to create environment friendly products such as biodegradable water bottles

3 0
3 years ago
Jeff decides that he would pay as much as $3,000 for a new laptop computer. He buys the computer and realizes consumer surplus o
Lady_Fox [76]

Jeff pay $2,300 for his computer.

b. $2,300

<u>Explanation:</u>

Consumer surplus can be defined as the amount that the consumer is willing to pay for a product or a service. The word surplus is a synonym for something extra or excess. It corresponds to the extra benefit that the consumer gets while buying something which may be the result of some discount, sale, or negotiation.  

Jeff realizes a consumer surplus of $700 while purchasing a laptop of $3000. As the consumer surplus is $700,

the amount Jeff has paid for the laptop is: $3000 - $700

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6 0
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