Answer:
To find the total variation in water level,I would multiply 1.8 by 2.2,equals 3.96.To check the answer, I would round the numbers and multiply them. Ex.: 2(2) =4. 4. Four is actually really close to 3.96!
Using the cosine function:
Solve for b:
![\begin{gathered} b=16\cdot\cos (45) \\ b=8\sqrt[]{2} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20b%3D16%5Ccdot%5Ccos%20%2845%29%20%5C%5C%20b%3D8%5Csqrt%5B%5D%7B2%7D%20%5Cend%7Bgathered%7D)
<span>B: To make the box, we need 2 triangular ends,
and 3 rectangular sides. Side the volume = 3240
and the height = 30, the area of each base (end) = 108.
The sides have areas of 30 x 42 = 720, and 30 x 15 = 450,
and there are 2 of those. So total area = 108 + 108 + 720 + 900 = 1836 cm^2
creds to yahoo answer
</span>
Step-by-step explanation:
2x-5=2x-6. First you collect like terms
2x-2x=-6+5
0=-1
This statement is false 0≠-1
The answer would be 16 S'mores and the limiting reactant would be the grahams.
(This is assuming that S'mores would need 2 grahams, 1 marshmallow and 1 chocolate piece.)
Limiting reactant would be the reactant that runs out first.
Let's take your problem into account and see what we have:
48 marshallows
32 grahams (2 x 16 per pack)
45 chocolate pieces (5 x 15 pieces per bar)
Since need 2 of the grahams per S'more then the maximum yield of the grahams is 16 S'mores.
The maximum yield of marshmallows is 48.
The maximum yield of chocolate is 45.
Since you cannot make S'mores without the grahams, then you can only make 16 S'mores before the grahams run out.
