Using the t-distribution, we have that the 95% confidence interval for the true mean number of pushups that can be done is (9, 21).
For this problem, we have the <u>standard deviation for the sample</u>, thus, the t-distribution is used.
- The sample mean is of 15, thus
. - The sample standard deviation is of 9, thus
. - The sample size is of 10, thus
.
First, we find the number of degrees of freedom, which is the one less than the sample size, thus df = 9.
Then, looking at the t-table or using a calculator, we find the critical value for a 95% confidence interval, with 9 df, thus t = 2.2622.
The margin of error is of:

Then:

The confidence interval is:

Then


The confidence interval is (9, 21).
A similar problem is given at brainly.com/question/25157574
B) thats the only one i could think of that would even sound right
Using algebraic equations, the number of points Yael has is calculated as: 29 points.
<h3>How to Use Algebraic Equations to Solve Word Problems?</h3>
In the given world problem, we known the following:
E = Eric
S = Shenna
Y = Yael
Their total points would be: E + S + Y = 68
S = 2(E) (Shenna has twice the points of Erik)
Y = S + 3 (Yael has three points more than Shenna)
We would therefore have the following algebraic equation:
E + 2E + (S + 3) = 68
Substitute S with 2E
E + 2E + 2E + 3 = 68
Solve for E
5E + 3 = 68
5E = 68 - 3
5E = 65
5E/5 = 65/5
E = 13
Eric's points is: 13
Yael's points = Y = S + 3
Y = S + 3 = 2E + 3
Plug in the value of E
Y = 2(13) + 3
Y = 26 + 3
Y = 29
Yael has 29 points.
Learn more about algebraic equation on:
brainly.com/question/2164351
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Answer:
Step-by-step explanation:
Express Courier Service has found that the delivery time for packages is normally distributed. So we use
z = (x - mean)/standard deviation
mean = 13
standard deviation = 2
x = time of delivery in hours
a) P(0 lesser than/equal to 18)
z = (18-13)/2 =5/2 = 2.5
Using the normal distribution table, the value is 0.9938
b) to be 95% sure, let the time be t
From the table, the equivalent of z that is 0.95 = 1.645
So 1.645 = (t-13)/2
t-13 = 3.29
t = 3.29+13= 16.29 hours