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jenyasd209 [6]
3 years ago
8

I picked the last one by accident but what is the correct answer?

Mathematics
2 answers:
kenny6666 [7]3 years ago
3 0
The third choice because -10 is greater than -14 and greater numbers are more towards the right.
Rufina [12.5K]3 years ago
3 0
The person above me is right
Go mark him/her brainliest
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You divide the answer and it will equal 12
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A school dedicated 20% of the courtyard area for students to start a garden. The students want to know how much of the 950-squar
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Answer:

190 square foot

Step-by-step explanation:

School yard = 950 square foot

20% of school yard for student to start garden

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20/100 x 950

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Find the value of two numbers is their sum is 21 and their difference is 3
kobusy [5.1K]

Hello from MrBillDoesMath

Answer:   12, 9

Discussion:

Let x be the first number and y the second number. The form the problem statement:

x + y = 21

x - y = 3


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8 0
3 years ago
Read 2 more answers
Recall, we have five connectives in propositional logic ¬, ∧, ∨, →, ↔ (negation, conjunction, disjunction, conditional and bicon
Free_Kalibri [48]

Answer:

(a) ¬(p→¬q)

(b) ¬p→q

(c) ¬((p→q)→¬(q→p))

Step-by-step explanation

taking into account the truth table for the conditional connective:

<u>p | q | p→q </u>

T | T |   T    

T | F |   F    

F | T |   T    

F | F |   T    

(a) and (b) can be seen from truth tables:

for (a) <u>p∧q</u>:

<u>p | q | ¬q | p→¬q | ¬(p→¬q) | p∧q</u>

T | T |  F  |   F     |    T       |  T

T | F |  T  |  T      |    F       |  F

F | T |  F  |  T      |    F       |  F

F | F |  T  |  T      |    F       |  F

As they have the same truth table, they are equivalent.

In a similar manner, for (b) p∨q:

<u>p | q | ¬p | ¬p→q | p∨q</u>

T | T |  F  |   T     |    T    

T | F |  F  |   T     |    T    

F | T |  T  |   T     |    T    

F | F |  T  |   F     |    F    

again, the truth tables are the same.

For (c)p↔q, we have to remember that p ↔ q can be written as (p→q)∧(q→p). By replacing p with (p→q) and q with (q→p) in the answer for part (a) we can change the ∧ connector to an equivalent using ¬ and →. Doing this we get ¬((p→q)→¬(q→p))

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Ddcvv was a great night for you guys I love ya too
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