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3 years ago

Que numero elevado a la potencia de 2 me da -16

Mathematics

1 answer:

zhenek [66]3 years ago

3 0

Answer:

Step-by-step explanation:

$x^2=-16\\4^2=16\\\\-4^2=-16\\x=-4$

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A 5-pound bag of apples costs $3.00. At the

NeX [460]

Answer:

$4.20

Step-by-step explanation:

Setup a ratio.

5/3=7/x

5x=7(3)

x=21/5

x=4.2 or for this problem 4.20

7 0

4 years ago

Help w one question plz

GarryVolchara [31]

Answer:

B is the right answer

Step-by-step explanation:

3 0

3 years ago

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How are Mass and distance related to gravity

docker41 [41]

Answer:

here.

Step-by-step explanation:

The force of gravity depends directly upon the masses of the two objects, and inversely on the square of the distance between them. This means that the force of gravity increases with mass, but decreases with increasing distance between objects.

I hope this helps! :D

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3 years ago

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Find the area of the sector

sergij07 [2.7K]

Answer:

$\boxed {\boxed {\sf a \approx 190.9 \ yd^2}}$

Step-by-step explanation:

There are 2 formulas for the area of a sector, but since we are given the central angle in degrees (not radians), we will use this formula:

$a= \frac {\theta}{360} \times \pi r^2$

Where θ is the central angle and r is the radius.

For this circle, the radius is 9 yards and the central angle is 270 degrees. We can substitute these values into the formula.

$a= \frac {270}{360} \times \pi \times (9 \ yd )^2$

Solve the fraction.

$a=0.75 \times \pi \times (9 \ yd)^2$

Solve the exponent.

(9 yd)²= 9 yd* 9 yd=81 yd²

$a= 0.75 \times \pi \times 81 \ yd^2$

Multiply all three numbers together.

$a= 190.851753706 \ yd^2$

The question asks us to round to the nearest tenth.

190.8<u>5</u>1753706

The 5 in the hundredth place tells us to round the 8 up to a 9.

$a \approx 190.9 \ yd^2$

The area of the sector is approximately <u>190.9 square yards. </u>

8 0

3 years ago

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If there is a nonmathematical symbol in the preceding expression, then your browser doesn't have the math symbol font. Please fo

horrorfan [7]

Complete Question

The complete question is shown on the first uploaded image

Answer:

$g(h(x)) = \sqrt[4]{x^2 + x +5} + 3$

$h(g(x)) = \sqrt{x} + 7\sqrt[4]{x} + 17$

$h(h(x)) = [x^2 + x + 5 ]^2 + x^2 + x + 10$

Step-by-step explanation:

From the question we are told that

$h(x) = x^2 + x + 5$

and

$g(x) = \sqrt[4]{x} + 3$

Considering first question

Now we are told g(h(x))

i.e

$g(h(x)) = [x^2 + x + 5 ]^{\frac{1}{4} } + 3$

=> $g(h(x)) = \sqrt[4]{x^2 + x +5} + 3$

Considering second question

Now we are told h(g(x))

i.e

$h(g(x)) = [x^{\frac{1}{4} } + 3]^2 + x^{\frac{1}{4} } + 3 + 5$

=> $h(g(x)) = x^{\frac{1}{2} } + 6x^{\frac{1}{4} } + 9+ x^{\frac{1}{4}} + 8$

=> $h(g(x)) = x^{\frac{1}{2}} + 7x^{\frac{1}{4}} + 17$

=> $h(g(x)) = \sqrt{x} + 7\sqrt[4]{x} + 17$

Considering third question

$h(h(x))= [x^2 + x + 5]^2 + [x^2 + x + 5 ] + 5$

=> $h(h(x)) = [x^2 + x + 5 ]^2 + x^2 + x + 10$

8 0

4 years ago