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Lorico [155]
3 years ago
6

How did the boundaries of the Mauryan Empire change under Aśoka?

Mathematics
1 answer:
OlgaM077 [116]3 years ago
5 0

Answer:

it expanded is the south

Step-by-step explanation:

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87500-(3.02x10^4) / 0.00000003
eduard
Sorry need points don't know the question
7 0
3 years ago
Find the area of the isosceles triangle. please help thanks
fiasKO [112]

Answer:

1080 m^2 Don't submit m^2 in your answer.

Step-by-step explanation:

Givens

The catch is to find h

To do that, use a^2 + b^2 = c^2

a b and c are in the same 1/2 triangle.

a = 48/2 = 24 m

b = h = ?

c = 51 meters

Solution

a^2 + b^2 = 51^2                      Substitute for b^2 = h^2

24^2 + h^2 = 51^2                   Expand 24^2 and 51^2

576 + h^2 = 2601                    Subtract 576 from both sides

h^2 = 2601 - 576

h^2 = 2025                              Take the square root of both sides

h = 45

Area

Area = 1/2 b * h

Area = 1/2 48 * 45

Area = 1080

Remark

Notice that to find h you only use 1/2 of 48 because that is the base of the right triangle.

To find the area, you need to use all of 48 because 48 is the full length of the base.

5 0
3 years ago
DUE SUN HELP ASAP BRAINIEST
trasher [3.6K]

Answer:  There are 108 hammers, and there are 36 screwdrivers. 36×3=108·

Step-by-step explanation: We know that there are more hammers than screwdrivers, so there are 36 screwdrivers but there are 3 times as many hammers so we multiply 36 by 3 to get 108.

3 0
3 years ago
A researcher wants to see if birds that build larger nests lay larger eggs. He selects two random samples of nests: one of small
True [87]

Answer:

95% confidence interval for the difference between the average mass of eggs in small and large nest is between a lower limit of 0.81 and an upper limit of 2.39.

Step-by-step explanation:

Confidence interval is given by mean +/- margin of error (E)

Eggs from small nest

Sample size (n1) = 60

Mean = 37.2

Sample variance = 24.7

Eggs from large nest

Sample size (n2) = 159

Mean = 35.6

Sample variance = 39

Pooled variance = [(60-1)24.7 + (159-1)39] ÷ (60+159-2) = 7619.3 ÷ 217 = 35.11

Standard deviation = sqrt(pooled variance) = sqrt(35.11) = 5.93

Difference in mean = 37.2 - 35.6 = 1.6

Degree of freedom = n1+n2 - 2 = 60+159-2 = 217

Confidence level = 95%

Critical value (t) corresponding to 217 degrees of freedom and 95% confidence level is 1.97132

E = t×sd/√(n1+n2) = 1.97132×5.93/√219 = 0.79

Lower limit = mean - E = 1.6 - 0.79 = 0.81

Upper limit = mean + E = 1.6 + 0.79 = 2.39

95% confidence interval for the difference in average mass is (0.81, 2.39)

3 0
3 years ago
sue has a monthly budget of 4300 after she gets done paying bills she usually has about 3% of the money left for random items ho
LuckyWell [14K]
You have to take 3% of 4300 which is $129.
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3 years ago
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