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2 years ago

What is the LCD of 5/6 and 7/8

Mathematics

1 answer:

Marizza181 [45]2 years ago

8 0

The LCD is 24 since 24 is the lowest number that is shared when you count by 6's and when you count by 8's

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I need help with math work

vichka [17]

1. 3/1

2. Will be positive. Aka always rational.

3. 3/1 + 3/1 = 6/2 = 3/1

6 0

3 years ago

2 3/5 convert to decinal

Leokris [45]

So we know that 1/5=0.2

Then we take 5/5=1.0

Then we solve 2*1.0=2.0

Now we solve 1/5+1/5+1/5 or 1/5*3=0.6

So then the correct answer is 2.6

Hope this helps!!!

7 0

3 years ago

2(8r+5)-3=4(4r-1)+11 is it an only solution or a no solution or infinite solution

pogonyaev

Answer:

Infinitely many solutions.

Step-by-step explanation:

Let's begin by carrying out the indicated multiplications, which must be done before any addition or subtraction:

2(8r+5)-3=4(4r-1)+11 becomes 16r + 10 - 3 = 16r - 4 + 11.

Subtracting 16r from both sides, we get 10 - 3 = - 4 + 11, or 7 = 7

This is always true, so we can conclude that this equation has infinitely many solutions.

3 0

2 years ago

A machine fills 75 bottles of water each minute. Write an equation to represent the number of bottles b of water the machine can

Len [333]

Answer:

b = 75m

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

A random sample of 10 shipments of stick-on labels showed the following order sizes.10,520 56,910 52,454 17,902 25,914 56,607 21

sammy [17]

Answer:

Confidence Interval: (21596,46428)

Step-by-step explanation:

We are given the following data set:

10520, 56910, 52454, 17902, 25914, 56607, 21861, 25039, 25983, 46929

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{340119}{10} = 34011.9$

Sum of squares of differences = 551869365.6 + 524322983.6 + 340111052.4 + 259528878 + 65575984.41 + 510538544 + 147644370.8 + 80512934.41 + 64463235.21 + 166851472.4 = 2711418821

$S.D = \sqrt{\frac{2711418821}{9}} = 17357.09$

Confidence interval:

$\mu \pm t_{critical}\frac{\sigma}{\sqrt{n}}$

Putting the values, we get,

$t_{critical}\text{ at degree of freedom 9 and}~\alpha_{0.05} = \pm 2.2621$

$34011.9 \pm 2.2621(\frac{17357.09}{\sqrt{10}} ) = 34011.9 \pm 12416.20 = (21595.7,46428.1) \approx (21596,46428)$

7 0

3 years ago