Answer:
9.4175
Step-by-step explanation:
Alright, from the graph, we know that Hannah's distance between hour 2 and hour 4 isn't uniform, so what we need to do is break the graph down a little.
When we break it down, we learn that Hannah's distance between hour 2 and hour 3 is decreasing because the y value decreases, and that Hannah's distance between hour 3 and hour 4 is increasing, because the y value starts increasing again.
Once we know that, all that's left is to match it up with the choices given. We can eliminate choices A and D because Hannah's distance between hour 2 and hour 4 isn't uniform, leaving us with B and C.
Between hours 2 and 3, we know that Hannah's distance is decreasing because the y value decreases, giving you your answer, which is C!
Use the chain rule:
<em>y</em> = tan(<em>x</em> ² - 5<em>x</em> + 6)
<em>y'</em> = sec²(<em>x</em> ² - 5<em>x</em> + 6) × (<em>x</em> ² - 5<em>x</em> + 6)'
<em>y'</em> = (2<em>x</em> - 5) sec²(<em>x</em> ² - 5<em>x</em> + 6)
Perhaps more explicitly: let <em>u(x)</em> = <em>x</em> ² - 5<em>x</em> + 6, so that
<em>y(x)</em> = tan(<em>x</em> ² - 5<em>x</em> + 6) → <em>y(u(x))</em> = tan(<em>u(x)</em> )
By the chain rule,
<em>y'(x)</em> = <em>y'(u(x))</em> × <em>u'(x)</em>
and we have
<em>y(u)</em> = tan(<em>u</em>) → <em>y'(u)</em> = sec²(<em>u</em>)
<em>u(x)</em> = <em>x</em> ² - 5<em>x</em> + 6 → <em>u'(x)</em> = 2<em>x</em> - 5
Then
<em>y'(x)</em> = (2<em>x</em> - 5) sec²(<em>u</em>)
or
<em>y'(x)</em> = (2<em>x</em> - 5) sec²(<em>x</em> ² - 5<em>x</em> + 6)
as we found earlier.
Answer:
m<RPS = 53 degrees
Step-by-step explanation:
Find the diagram attached
From the diagram shown;
m<QPR + m<RPS = 90
Given that;
m<QPR = x
m<RPS = x+16
Substitute into the formula;
m<QPR + m<RPS = 90
x+x+16 = 90
2x+16 = 90
2x = 90-16
2x = 74
x = 74/2
x = 37degrees
Get m<RPS;
Since m<RPS = x+16
m<RPS = 37 + 16
m<RPS = 53 degrees
Answer:
D. 0.7x+10.8
Step-by-step explanation:
I used desmos calculator and typed in all the equations and this is the only one that was close to the set of dots. I attached a screetshot so you can look for yourself. I hope this helps
