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777dan777 [17]
3 years ago
12

I need help within the next 15 mins

Mathematics
1 answer:
abruzzese [7]3 years ago
3 0

Answer:30

Step-by-step explanation: LxW (length x Width) 3x10=30.... Hope this helps... if you break it down then you can write down (10) on your page but the answer is 30

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find the length and width of a rectangle that has an area of 968 square feet and whose perimeter is a minimum
andrezito [222]
The question isn't finished...
3 0
3 years ago
the percent p of the u.s. population with internet access is given by 25p-34t=1378 where t is the number of years after 1990. wh
Mashutka [201]

Answer:

  • Hence, 75.52 percent of the u.s. population had internet access in 2005.
  • After 25 years or in the year 2015 89% have internet access.

Step-by-step explanation:

the percent p of the u.s. population with internet access is given by:

25 p-34 t=1378

where t is the number of years after 1990.

  • We are asked to find  what percent of the u.s. population had internet access in 2005 i.e. we need to find the value of p after 15 years i.e. t=15.

⇒  25p-34×(15)=1378

⇒  25p-510=1378

⇒  25p=1378+510

⇒  25p=1888

⇒  p=75.52

Hence, 75.52 percent of the u.s. population had internet access in 2005.

  • Next we are asked to find in what year will 89% have internet access?

i.e. we have to find the value of t when we are given p=89

⇒  25×89-34t=1378

⇒  2225-34t=1378

⇒  2225-1378=34t

⇒  847=34t

⇒  or 34t=847

⇒  t=24.9112≈25

Hence after 25 years 89% will have internet access.

i.e. in the year 2015 89% will have internet access.



3 0
3 years ago
Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!
lora16 [44]

Answer:

6

Step-by-step explanation:

because I think I'm right

3 0
3 years ago
Read 2 more answers
Please help me ill give you the crown thing if its right
aleksandrvk [35]

Answer:10x + 30

Step-by-step explanation:

5 0
3 years ago
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Find the x-coordinates of any relative extrema and inflection point(s) for the function f(x)= 6x^1/3 + 3x^4/3. You must justify
irina [24]

Answer:

x-coordinates of relative extrema = \frac{-1}{2}

x-coordinates of the inflexion points are 0, 1

Step-by-step explanation:

f(x)=6x^{\frac{1}{3}}+3x^{\frac{4}{3}}

Differentiate with respect to x

f'(x)=6\left ( \frac{1}{3} \right )x^{\frac{-2}{3}}+3\left ( \frac{4}{3} \right )x^{\frac{1}{3}}=\frac{2}{x^{\frac{2}{3}}}+4x^{\frac{1}{3}}

f'(x)=0\Rightarrow \frac{2}{x^{\frac{2}{3}}}+4x^{\frac{1}{3}}=0\Rightarrow x=\frac{-1}{2}

Differentiate f'(x) with respect to x

f''(x)=2\left ( \frac{-2}{3} \right )x^{\frac{-5}{3}}+\frac{4}{3}x^{\frac{-2}{3}}=\frac{-4x^{\frac{2}{3}}+4x^{\frac{5}{3}}}{3x^{\frac{2}{3}}x^{\frac{5}{3}}}\\f''(x)=0\Rightarrow \frac{-4x^{\frac{2}{3}}+4x^{\frac{5}{3}}}{3x^{\frac{2}{3}}x^{\frac{5}{3}}}=0\Rightarrow x=1

At x = \frac{-1}{2},

f''\left ( \frac{-1}{2} \right )=\frac{4\left ( -1+4\left ( \frac{-1}{2} \right ) \right )}{3\left ( \frac{-1}{2} \right )^{\frac{5}{3}}}>0

We know that if f''(a)>0 then x = a is a point of minima.

So, x=\frac{-1}{2} is a point of minima.

For inflexion points:

Inflexion points are the points at which f''(x) = 0 or f''(x) is not defined.

So, x-coordinates of the inflexion points are 0, 1

7 0
3 years ago
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