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Tom [10]
3 years ago
9

I need help on this?

Mathematics
1 answer:
ValentinkaMS [17]3 years ago
6 0

Answer:

49º

Step-by-step explanation:

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At a track meet , 10 different runners compete in the 1600m run.
Zanzabum

Answer:

There are 3,628,800 different ways for the runners to finish.

Step-by-step explanation:

Arrangments of x elements:

The number of possible arrangments of x elements is given by the following formula:

A_{x} = x!

In this question:

10 different runners, which means that the number of different ways that there are for the runners to finish is an arrangment of 10 elements. So

A_{10} = 10! = 3628800

There are 3,628,800 different ways for the runners to finish.

4 0
3 years ago
The perimeter of a square is 75 inches. What is the length of one side of the square?
bulgar [2K]

Answer:

18.75 inches

Step-by-step explanation:

Believe me friend

7 0
3 years ago
Read 2 more answers
Please help Im timed!
Natalka [10]
15:10
3:2
Hope this helps :)

4 0
4 years ago
A deck of 52 cards contains 12 picture cards. If the 52 cards are distributed in a random manner among four players in such a wa
Mkey [24]

Answer:

The probability that each player will receive three picture cards = 0.0324

Step-by-step explanation:

As given,

A deck of 52 cards contains 12 picture cards

Remaining card = 52 - 12 = 40

So,

Total number of ways in which 12 picture card is distributed = \frac{12!}{3! 3! 3! 3!}

Now,

The Total number of ways in which Remaining cards are distributed = \frac{40!}{10! 10! 10! 10!}

So,

Total number of ways of getting 3 picture card and remaining card = \frac{12!}{3! 3! 3! 3!}× \frac{40!}{10! 10! 10! 10!}

= \frac{12! 40!}{(3!)^{4} (10!)^{4}  }

Now,

Total number of ways to distribute 52 cards so that each people get 13 card = \frac{52!}{13! 13! 13! 13!} = \frac{52!}{ (13!)^{4} }

∴ The probability = \frac{\frac{12! 40!}{(3!)^{4} (10!)^{4}  }}{\frac{52!}{(13!)^{4} }}

                            = \frac{12! 40!}{(3!)^{4} (10!)^{4}  }×\frac{(13!)^{4} }{ 52! }

                           = \frac{12! 40!}{(3!)^{4} (10!)^{4}  }×\frac{(13.12.11.10!)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41.40! }

                           = \frac{12!}{(3!)^{4}   }×\frac{(13.12.11)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41}

                           = \frac{479,001,600}{(6)^{4}   }×\frac{(1716)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41}

                           = 0.0324

∴ we get

The probability that each player will receive three picture cards = 0.0324

6 0
3 years ago
Solve each Algebraic Equation
Alexus [3.1K]

Answer:

x=83

y=69

k=71

a=117

q=51

x=9

p=-42

Step-by-step explanation:

4 0
3 years ago
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