Answer:t a particular point it is exactly above the fish moving in a pond 3m below the ground level. Find the vertical distance between these two points.? is done on EduRev Study Group by Class 7 Students. The Questions and Answers of A kite is flying at a height of 10m above the ground level. At a particular point it is exactly above the fish moving in a pond 3m below the ground level.
Step-by-step explanation:
Answer:
First term a = 41
Step-by-step explanation:
Arithmetic Progression:
Common differences d = -2
![S_{n}=\frac{n}{2}(2a+[n-1]d)\\\\S_{20}=\frac{20}{2}(2a+19*[-2])\\\\](https://tex.z-dn.net/?f=S_%7Bn%7D%3D%5Cfrac%7Bn%7D%7B2%7D%282a%2B%5Bn-1%5Dd%29%5C%5C%5C%5CS_%7B20%7D%3D%5Cfrac%7B20%7D%7B2%7D%282a%2B19%2A%5B-2%5D%29%5C%5C%5C%5C)
= 10*(2a - 38)
= 10*2a - 10*38
=20a - 380
![S_{22}=\frac{22}{2}(2a+21*[-2])\\\\](https://tex.z-dn.net/?f=S_%7B22%7D%3D%5Cfrac%7B22%7D%7B2%7D%282a%2B21%2A%5B-2%5D%29%5C%5C%5C%5C)
= 11 (2a -42)
=11*2a - 11*42
= 22a - 462

22a - 462 = 20a - 380
22a = 20a - 380 + 462
22a = 20a + 82
22a - 20a = 82
2a = 82
a = 82/2
a = 41
First term a = 41
Answer:
1.14 liters
Step-by-step explanation:
We have 8% glycerin solution and we need to make it 16% glycerin solution [more concentration].
When we add "x" liters, we add glycerin as well as changes the total. in 12 Liters, there is 12 * 0.08 = 0.96Liters of glycerin. How much we need to add to this??
Note, 16% = 0.16
We can write a Ratio as shown below, cross multiply and solve for x:

We need to add around 1.14 liters
Answer:
10 meters
Step-by-step explanation:
The given function
represents the height,
, in meters,
seconds after the ball is thrown.
Since the ball is thrown off the roof, then ball's height will be equal to the roof's height before being thrown (0 seconds). Therefore, substitute
into the given function
:

Therefore, the building is 10 meters tall.
Answer:
C
Step-by-step explanation: