I'm taking radius to be half of the side length.Then one side is 26 cm and the area of a square is the length of a side squared.A=26^2=676So,C) 676
Answer:
11
Step-by-step explanation:
17 ft=17x12=204 inches
204/18=11.333...
So you can cut 11 logs
Answer:
From the graph, it is clear that the point of intersection is:
And the x-coordinate of the point of intersection for the two lines is:
Step-by-step explanation:
- As we know that the solution of the system of equations is the point of intersection. Let us solve it.
Given the system of equations
![\begin{bmatrix}2x+y=-9\\ 2x-5y=-3\end{bmatrix}](https://tex.z-dn.net/?f=%5Cbegin%7Bbmatrix%7D2x%2By%3D-9%5C%5C%202x-5y%3D-3%5Cend%7Bbmatrix%7D)
solving the system of equations
subtracting 2x+y = -9 from 2x-5y = -3
![2x-5y=-3](https://tex.z-dn.net/?f=2x-5y%3D-3)
![-](https://tex.z-dn.net/?f=-)
![\underline{2x+y=-9}](https://tex.z-dn.net/?f=%5Cunderline%7B2x%2By%3D-9%7D)
![-6y=6](https://tex.z-dn.net/?f=-6y%3D6)
so
![\begin{bmatrix}2x+y=-9\\ -6y=6\end{bmatrix}](https://tex.z-dn.net/?f=%5Cbegin%7Bbmatrix%7D2x%2By%3D-9%5C%5C%20-6y%3D6%5Cend%7Bbmatrix%7D)
solving for y
![-6y=6](https://tex.z-dn.net/?f=-6y%3D6)
Divide both sides by -6
![\frac{-6y}{-6}=\frac{6}{-6}](https://tex.z-dn.net/?f=%5Cfrac%7B-6y%7D%7B-6%7D%3D%5Cfrac%7B6%7D%7B-6%7D)
![y=-1](https://tex.z-dn.net/?f=y%3D-1)
![\mathrm{For\:}2x+y=-9\mathrm{\:plug\:in\:}y=-1](https://tex.z-dn.net/?f=%5Cmathrm%7BFor%5C%3A%7D2x%2By%3D-9%5Cmathrm%7B%5C%3Aplug%5C%3Ain%5C%3A%7Dy%3D-1)
![2x-1=-9](https://tex.z-dn.net/?f=2x-1%3D-9)
![2x=-8](https://tex.z-dn.net/?f=2x%3D-8)
Divide both sides by 2
![\frac{2x}{2}=\frac{-8}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B2x%7D%7B2%7D%3D%5Cfrac%7B-8%7D%7B2%7D)
![x=-4](https://tex.z-dn.net/?f=x%3D-4)
Thus, the x-coordinate of the point of intersection for the two lines below will be:
![x=-4](https://tex.z-dn.net/?f=x%3D-4)
Also, the graph is attached.
From the graph, it is clear that the point of intersection is:
And the x-coordinate of the point of intersection for the two lines is: