Answer: look at my work its 10 pi cm ^2
Step-by-step explanation:
<u>Answer-</u>
<em>The probability that in the box there are 1 red and 8 blue markers is</em><em> 0.111 or 11.1%</em>
<u>Solution-</u>
In the box all markers are red or blue. There are total of 9 markers.
So the number of possible combination number of red or blue marker is,
As at the random drawn, there was a Blue marker, so the condition of (9,0) i.e 9 Red marker and 0 Blue marker is not a case.
So the sample space becomes,
Let us assume that E is the event that in the box there are 1 red and 8 blue markers. So
The probability that in the box there are 1 red and 8 blue markers is,
Answer:
M+16m
Step-by-step explanation:
-9m+9 cancel eachother out because it is a negative and a postive value, so you would just put the variable. For 8m+8 it would be 16m because the sre both positive so you would add them like normal
Answer:
10 4/7
Step-by-step i used photo math