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2 years ago

Which system of equations is represented by the matrix below?

Mathematics

1 answer:

egoroff_w [7]2 years ago

6 0

9514 1404 393

Answer:

Step-by-step explanation:

In order for the matrix to represent the equations, the coefficients in the equations need to match the terms in the matrix. That is only the case for choice B.

Details are important in math.

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A new electric car uses 7.3% of its battery to drive 6.4 miles, at that rate how many miles can you drive using 100% of the batt

Natali [406]

Answer:

83.2 miles

Step-by-step explanation:

what i had to do was multiply 7.3 by 13 and that was 94.9 that was as close as i could get it to 100 so i then multipled 6.4 by 13 and got 83,2 miles

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2 years ago

What’s the answer to (-8x) + x + (-2x)

Tresset [83]

$(-8x) + x + (-2x) = -8x + x - 2x = -9x$

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3 years ago

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A solution initially contains 200 bacteria. 1. Assuming the number y increases at a rate proportional to the number present, wri

GuDViN [60]

Answer:

1. $\frac{dy}{dt}=ky$

2.543.6

Step-by-step explanation:

We are given that

y(0)=200

Let y be the number of bacteria at any time

$\frac{dy}{dt}$ =Number of bacteria per unit time

$\frac{dy}{dt}\proportional y$

$\frac{dy}{dt}=ky$

Where k=Proportionality constant

2. $\frac{dy}{y}=kdt$ ,y'(0)=100

Integrating on both sides then, we get

$lny=kt+C$

We have y(0)=200

Substitute the values then , we get

$ln 200=k(0)+C$

$C=ln 200$

Substitute the value of C then we get

$ln y=kt+ln 200$

$ln y-ln200=kt$

$ln\frac{y}{200}=kt$

$\frac{y}{200}=e^{kt}$

$y=200e^{kt}$

Differentiate w.r.t

$y'=200ke^{kt}$

Substitute the given condition then, we get

$100=200ke^{0}=200 \;because \;e^0=1$

$k=\frac{100}{200}=\frac{1}{2}$

$y=200e^{\frac{t}{2}}$

Substitute t=2

Then, we get $y=200e^{\frac{2}{2}}=200e$

$y=200(2.718)=543.6=543.6$

e=2.718

Hence, the number of bacteria after 2 hours=543.6

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3 years ago

Help me asap (please please)

CaHeK987 [17]

Area of a circle = pi*r^2.

Here, A = 380.13 mi. Unfortunately, "mi" is NOT a unit of area.

So I will assume that the problem should read A = 380.13 sq. miles.
380.12 mi^2
Thus, 380.13 mi^2 = 3.14*r^2, and r^2 = ------------------- 121.057 mi^2
3.14

The radius is the sqrt of 121.057 mi^2: 11.00 miles.

The diam. is twice that, or d = 22.00 miles.

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choli [55]

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