Find the ratio in simlest form of 221 to 289
1 answer:
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Step-by-step explanation:
Hey there!!!
Here,
Given, A line passes through point (2,-2) and is perpendicular to the y= 5x+2.
The equation of a straight line passing through point is,
Now, put all values.
It is the 1st equation.
Another equation is;
y = 5x +2........(2nd equation).
Now, Comparing it with y = mx + c, we get;
m2=5
As per the condition of perpendicular lines,
m1×m2= -1
m1 × 5 = -1
Therefore, m2= -1/5.
Keeping the value of m1 in 1st equation.
Simplify them.
Therefore the required equation is x+5y+8= 0.
<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
Answer:
Step-by-step explanation:
Consider a sketch of the problem as shown in the picture, where:
- Blue line is given by y = 4x + 1.
- Point B is the center of the circle.
- Point A is (-3, 0).
Since the center of the circle lies on the line y = 4x +1 and is tangent to the x-axis at point A, then its radius BA is perpendicular to the x-axis. To find the coordinates of point B, we must replace x = -3 into the blue line equation: y = 4x(-3) + 1 = -11.
So, we know that the center of the circle is at B=(-3, -11). And furthermore, the radius BA is of length r=11.
Since the <em>general equation of the circle</em> of radius lenght r centered at (h, k) is given by
then with h = -3, k = -11 and r= 11, the equation of our circle is
