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3 years ago

If the circumfrences is 10m, where can we susbistute 10 into the equation C= pi diameter.

Mathematics

2 answers:

Ahat [919]3 years ago

8 0

Answer:

You can pit 10 in for the C so it will be 10=radius squared or it could be 10=diameter

Step-by-step explanation:

C stands for circumference

Genrish500 [490]3 years ago

6 0

Answer:

Step-by-step explanation:

It would be 10 = pi diameter bc 10 is the circumfrernce. so that'd be B

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The histogram below shows the heights, rounded to the nearest inch, of the members of the Oak High School basketball team. A. 1

Elan Coil [88]

Answer:

Range of player's height = 9 inch

Step-by-step explanation:

Given:

Number of players Height range

4 66-67

8 68 -69

14 70-71

9 72-73

1 74-75

Find:

Range of player's height

Computation:

Range = Maximum value - Minimum Value

Range of player's height = Maximum height of a player - height of a player

Range of player's height = 75 inch - 66 inch

Range of player's height = 9 inch

5 0

2 years ago

Which of the following expresses 16 + 36 by using the GCF of the two numbers?

sergij07 [2.7K]

16 + 36 = 52 so the answer would be A) 4(4 + 9) because that equals 52 as well.

6 0

3 years ago

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A square + b square =

dmitriy555 [2]

c square

its making me write 20 more characters

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8 0

3 years ago

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We're testing the hypothesis that the average boy walks at 18 months of age (H0: p = 18). We assume that the ages at which boys

marusya05 [52]

Answer:

II. This finding is significant for a two-tailed test at .01.

III. This finding is significant for a one-tailed test at .01.

d. II and III only

Step-by-step explanation:

1) Data given and notation

$\bar X=19.2$ represent the battery life sample mean

$\sigma=2.5$ represent the population standard deviation

$n=25$ sample size

$\mu_o =18$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

2) State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean battery life is equal to 18 or not for parta I and II:

Null hypothesis: $\mu = 18$

Alternative hypothesis: $\mu \neq 18$

And for part III we have a one tailed test with the following hypothesis:

Null hypothesis: $\mu \leq 18$

Alternative hypothesis: $\mu > 18$

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

3) Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{19.2-18}{\frac{2.5}{\sqrt{25}}}=2.4$

4) P-value

First we need to calculate the degrees of freedom given by:

$df=n-1=25-1=24$

Since is a two tailed test for parts I and II, the p value would be:

$p_v =2*P(t_{(24)}>2.4)=0.0245$

And for part III since we have a one right tailed test the p value is:

$p_v =P(t_{(24)}>2.4)=0.0122$

5) Conclusion

I. This finding is significant for a two-tailed test at .05.

Since the $p_v$ . We reject the null hypothesis so we don't have a significant result. FALSE

II. This finding is significant for a two-tailed test at .01.

Since the $p_v >\alpha$ . We FAIL to reject the null hypothesis so we have a significant result. TRUE.

III. This finding is significant for a one-tailed test at .01.

Since the $p_v >\alpha$ . We FAIL to reject the null hypothesis so we have a significant result. TRUE.

So then the correct options is:

d. II and III only

6 0

3 years ago

cody's Bikes rents bikes for $18 plus $5 per hour. Mark paid $48 to rent a bike. For how many hours did he rent the bike.

kkurt [141]

He rented the bike for 6 hours. If Cody charges an 18 dollar fee up front you subtract that from the total 48 to get 30. Then once you get down to the what he payed for the time used you divide it by 5 because that’s the hourly fee and get 6 hours

4 0

3 years ago

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