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Luba_88 [7]
3 years ago
6

WILL MARK YOU BRAINLIEST HELP ASAP

Mathematics
1 answer:
dsp733 years ago
5 0

Answer:

That big "E" word means the same lengths so they are all 14" long

Step-by-step explanation:

plz brainliest me! XD

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PLEASE HELP! WILL GIVE BRAINLIEST!
VMariaS [17]

Answer:

Answer: the equivalent form of 6(2x+3x+10) are 12x+18x + 60 and 30x+60.

Hope this helps

8 0
3 years ago
Read 2 more answers
If you apply the changes below to the linear parent function, Fx) = x, what is
Inga [223]

Answer: A. G(x)= ax=y= - f(x) is flip over x-axis. Therefore, f(x) =14x would become f(x) =-14x. Therefore, final transformed function f(x)=-14x is vertically stretch by a factor of 14 and flip over the x-axis.

5 0
3 years ago
Pleaseeeeeee help mee
BlackZzzverrR [31]

Answer:

The solution of the given trigonometric equation

                   x = \frac{\pi }{6}

Step-by-step explanation:

<u><em>Step(i):</em></u>-

Given  

                cos( 3x - \frac{\pi }{3} )  = \frac{\sqrt{3} }{2}

                  cos( 3x - \frac{\pi }{3} )  = cos (\frac{\pi }{6} )

                      3x - \frac{\pi }{3}  =  \frac{\pi }{6}

                      3x - \frac{\pi }{3  } + \frac{\pi }{3}   =  \frac{\pi }{6} + \frac{\pi }{3}

                      3x = \frac{2\pi +\pi }{6} = \frac{3\pi }{6} = \frac{\pi }{2}

                     x = \frac{\pi }{6}

<u><em>Step(ii)</em></u>:-

The solution of the given trigonometric equation

                   x = \frac{\pi }{6}

<u><em>verification </em></u>:-

      cos( 3x - \frac{\pi }{3} )  = \frac{\sqrt{3} }{2}

put  x = \frac{\pi }{6}

    cos( 3(\frac{\pi }{6})  - \frac{\pi }{3} )  = \frac{\sqrt{3} }{2}

    cos (\frac{\pi }{6} ) = \frac{\sqrt{3} }{2} \\\\\frac{\sqrt{3} }{2} =  \frac{\sqrt{3} }{2}

Both are equal

∴The solution of the given trigonometric equation

                   x = \frac{\pi }{6}

                     

4 0
2 years ago
What are the equations of the asymptotes of the graph of the function f(x)=3x^2-2x-1/x^2+3x-10
kotykmax [81]
Ik one for sure is a horizontal asmym which is   3 
7 0
3 years ago
If the diagonal of a square is 12 to the square root of two then what is the area of the square
erastovalidia [21]

Answer:

Let there be a square ABCD with diagonal AC=12 root 2 cm

Since angles of a square are all 90 degrees

pythagoras theoream

AB^2+BC^2=AC^2

Since all sides of square are equal

2AB^2=(12 root 2)^2

2AB ^2=144*2

AB^2=144

AB= root 144=12 cm

area of square = s^2 =12^2 = 144cm^2

hope it helps

Step-by-step explanation:

3 0
3 years ago
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