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jarptica [38.1K]
3 years ago
12

a) A box contains 6 red balls, 4 white balls, and 10 black balls. Two balls are drawn at random from the box (with replacement o

f the first before the second is drawn). What is the probability of getting a red ball on the first draw and a white ball on the second
Mathematics
1 answer:
statuscvo [17]3 years ago
5 0

Answer:

Red ball=3/10

White ball=1/5

Step-by-step explanation:

Red balls=6. And all the balls are equal to 20. So probability of red ball=6/20=3/10.

White balls=4. So probability of white ball=4/20=1/5.

NB: Since the first ball was replaced, there's no need to deduct a ball from the original 20 balls.

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Step-by-step explanation:

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<h2>Question:</h2>

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