Answer:
7% does not represent the part 0.7 of the push-ups Malik completes because 7% is NOT equivalent to 0.7.
Step-by-step explanation:
Given that Malik completes 0.7 of the total number of push-ups his coach requires.
<u>Checking the given options:</u>
7% = 7/100 = 0.07
14/20 = 0.7
70% = 70/100 = 7/10 = 0.7
0.70 = 0.7
Therefore,
7% does not represent the part 0.7 of the push-ups Malik completes because 7% is NOT equivalent to 0.7.
Answer:
r = 7
Step-by-step explanation:
The equation of a circle centred at the origin is
x² + y² = r² ( where r is the radius )
x² + y² = 49 ← is in this form
with r² = 49 ⇒ r =
= 7
Go to this website it should help you http://www.mathx.net/inequalities/
divide smaller number by larger number
210000/250000 = 0.84
1.00 - 0.84 = 0.16 = 16%
the price dropped by 16%
ANSWER
A. x = 2, √11, -√11
EXPLANATION
To find the zeros of f, which is a 3rd-degree polynomial, we can try some common values to see if any of them is a zero: 1, 2, -1, -2. In this case 2 is a zero of the function:
![\begin{gathered} f(2)=2\cdot2^3-4\cdot2^2-22\cdot2+44 \\ f(2)=2\cdot8-4\cdot4-44+44 \\ f(2)=16\cdot16 \\ f(2)=0 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20f%282%29%3D2%5Ccdot2%5E3-4%5Ccdot2%5E2-22%5Ccdot2%2B44%20%5C%5C%20f%282%29%3D2%5Ccdot8-4%5Ccdot4-44%2B44%20%5C%5C%20f%282%29%3D16%5Ccdot16%20%5C%5C%20f%282%29%3D0%20%5Cend%7Bgathered%7D)
Now we can reduce our polynomial by dividing it by the factor (x - 2) and obtain a 2nd-degree polynomial, whose zeros are easier to find:
So we can rewrite f(x) as:
![f(x)=(x-2)(2x^2-22)](https://tex.z-dn.net/?f=f%28x%29%3D%28x-2%29%282x%5E2-22%29)
To find the other two zeros we have to solve:
![2x^2-22=0](https://tex.z-dn.net/?f=2x%5E2-22%3D0)
Add 22 to both sides of the equation:
![\begin{gathered} 2x^2-22+22=0+22 \\ 2x^2=22 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%202x%5E2-22%2B22%3D0%2B22%20%5C%5C%202x%5E2%3D22%20%5Cend%7Bgathered%7D)
Divide both sides by 2:
![\begin{gathered} \frac{2x^2}{2}=\frac{22}{2} \\ x^2=11 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Cfrac%7B2x%5E2%7D%7B2%7D%3D%5Cfrac%7B22%7D%7B2%7D%20%5C%5C%20x%5E2%3D11%20%5Cend%7Bgathered%7D)
And take square root. Remember that the square root has a positive and a negative result:
![\begin{gathered} \sqrt[]{x^2}=\pm\sqrt[]{11} \\ x=\pm\sqrt[]{11} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Csqrt%5B%5D%7Bx%5E2%7D%3D%5Cpm%5Csqrt%5B%5D%7B11%7D%20%5C%5C%20x%3D%5Cpm%5Csqrt%5B%5D%7B11%7D%20%5Cend%7Bgathered%7D)
So the other two zeros are √11 and -√11.
The three real zeros of f are 2, √11 and -√11