I can not set up a 2 way table online but what they want is a collom of the information neatly laid out...
With the 9th graders in one collom and the 10th graders in the other
like this
9th grader 10th grader
# of students 32 40
# of participated 32 18
Draw this out with lines and it will be correct.
I hope this helps GOOD LUCK...this is tough math for a middle schooler.
Answer:
x=26
Step-by-step explanation:
3x +12 =90
subtract 12 from each side
3x=78
divide 3 from each side
x=26
You will have 233 animals left.
Answer:
7 horses and 8 chickens
Step-by-step explanation:
To solve this, first you would need to list out all of the available ratios. Then, find out how many legs are in each option.:
14 horses and 1 chicken = 58 legs
13 horses and 2 chickens = 56 legs
12 horses and 3 chickens = etc.
11 horses and 4 chickens
10 horses and 5 chickens
9 horses and 6 chickens
8 horses and 7 chickens
7 horses and 8 chickens = 44 legs!
6 horses and 9 chickens
5 horses and 10 chickens
4 horses and 11 chickens
3 horses and 12 chickens
2 horses and 13 chickens
1 horses and 14 chickens
Each new term of this arith. seq. is obtained by adding 4 to the previous term. Hence, 15 = 11+4; 19=15+4, and so on. Add 4 to 19 to get the next term. Keep going until you have 4 new terms for the arith. seq. 11, 15, 19, .....
