Now, multiply both sides by 6 and you get.....
df+10=6g
now, subtract 10 on both sides and you get.....
df=6g-10
now divide both sides by d to get f by itself and you get........
It has been determined that the number of fish f(t) that can be caught in t minutes in a certain pond using a certain bait is f(t) = .25t + 1, for t > 10. Find the number of fish that can be caught if you fish for 15 minutes. Round your answer to the nearest whole number.
9514 1404 393
Answer:
- 0 ≤ m ≤ 7
- 0.4541 cm/month; average rate of growth over last 4 months of study
Step-by-step explanation:
<u>Part A</u>:
The study was concluded after 7 months. The fish cannot be expected to maintain exponential growth for any significant period beyond the observation period. A reasonable domain is ...
0 ≤ m ≤ 7
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<u>Part B</u>:
The y-intercept is the value when m=0. It is the length of the fish at the start of the study.
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<u>Part C</u>:
The average rate of change on the interval [3, 7] is given by ...
(f(7) -f(3))/(7 -3) = (4(1.08^7) -4(1.08^3))/4 = 1.08^3·(1.08^4 -1)
≈ 0.4541 cm/month
This is the average growth rate of the fish in cm per month over the period from 3 months to 7 months.
Answer:
15 rides= 40 and r rides= 10+2r
Step-by-step explanation: