Answer?? please i need this

Month after month, Jessica is overspending in her budget and decreasing her savings account balance as a result. Which action wo

Black_prince [1.1K]

Answer:

no

Step-by-step explanation:

6 0

3 years ago

What is the solution to this system of equations? 2t + w = 10 4t = 20 − 2w A. It has no solution. B. It has infinite solutions.

joja [24]

Answer:

<h3>B. It has infinite solutions</h3>

Step-by-step explanation:

Given the system of equations:

2t + w = 10 ..... 1

4t = 20 − 2w ... 2

From 1:

w = 10-2t ...3

Substitute 3 into 2 to have;

4t = 20 - 2(10-2t)

4t = 20-20+4t

4t = 4t

Let t = k

Substitute t = k into 1 and get w;

From 1: 2t + w = 10

2k + w =10

w = 10 - 2k

<em>k can take any integers. This shows that the solution to the equation is infinite</em>

7 0

3 years ago

Rachel harvested half as many watermelons as strawberries. If there ere 28 watermelons, how many strawberries did she get?

iren [92.7K]

Answer:

its 28

Step-by-step explanation:

8 0

3 years ago

Need help on 9 and 10

Wewaii [24]

9.) The relation can not be a function only if the domain is the same. If you plot the points on a graph and use the Vertical Line Test(VLT) you would see that none of the points would be on the same line. It doesn't matter if the range is the same

10.)On the graph your y-intercept would be 2 so that is where you plot your first point. In order to find the slope you need to go up three spaces and one space to the left this is also known as "rise over run". *Remember you always go up spaces for "rise over run" but if the slope is positive then you go to the right and if its negative you go to the left.

I hope this helps love! :)

4 0

3 years ago

. Exam scores for a large introductory statistics class follow an approximate normal distribution with an average score of 56 an

Andru [333]

Answer:

0.1% probability that the average score of a random sample of 20 students exceeds 59.5.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 56, \sigma = 5, n = 20, s = \frac{5}{\sqrt{20}} = 1.12$