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Nutka1998 [239]
3 years ago
9

Write two properties of 1​

Mathematics
2 answers:
valentinak56 [21]3 years ago
5 0
  1. Any number multiplied by 1 stays the same.
  2. 1 is called the multiplicative identity .

SIZIF [17.4K]3 years ago
4 0

The identity property of 1 says that any number multiplied by 1 keeps its identity. In other words, any number multiplied by 1 stays the same. The reason the number stays the same is because multiplying by 1 means we have 1 copy of the number. For example, 32x1=32.

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Please help I don't understand!
levacccp [35]

Answer:

9

Step-by-step explanation:

Take the sides in proportion.

⇒ \frac{AE}{AD} =\frac{AB}{AC}

⇒ \frac{12}{12+8} =\frac{x}{15}

⇒ \frac{12}{20} =\frac{x}{15}

⇒ \frac{3}{5} =\frac{x}{15}

⇒ 3 = \frac{x}{3}

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2 years ago
Given equations A and B as 2/5x+y=12 and 5/2y-x=6 respectively which expression will eliminate the variable X a) 5/2A+2/5B b)5/2
frutty [35]

Answer:

C) A+\frac{2}{5}B

Step-by-step explanation:

Given Equations:

A) \frac{2}{5}x+y=12

B) \frac{5}{2}y-x=6

In order to eliminate x we need to multiply \frac{2}{5} to equation B and add it to A.

Multiplying \frac{2}{5} to B.

⇒ \frac{2}{5}\times (\frac{5}{2}y-x)=\frac{2}{5}\times 6

⇒ (\frac{2}{5}\times\frac{5}{2}y)-(\frac{2}{5}x)=\frac{12}{5}

⇒ y-\frac{2}{5}x=\frac{12}{5}

Adding it equation A.

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+ -\frac{2}{5}x+y=\frac{12}{5}

We get 2y=\frac{72}{5}

Thus x is eliminated.

So, the expression used to eliminate x is:

A+\frac{2}{5}B

4 0
3 years ago
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ivann1987 [24]

Answer:

140

Step-by-step explanation:

tell me if I'm wrong

60+60+20=140

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Answer:

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Step-by-step explanation:

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⇒ 28-x>7x-28

⇒ 56>8x

⇒ 7>x

⇒ x

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