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Answer:
I'm getting points
Step-by-step explanation:
so I can ask questionss
Answer:
Yes , function is continuous in [0,2] and is differentiable (0,2) since polynomial function are continuous and differentiable
Step-by-step explanation:
We are given the Function
f(x) =
The two basic hypothesis of the mean valued theorem are
- The function should be continuous in [0,2]
- The function should be differentiable in (1,2)
upon checking the condition stated above on the given function
f(x) is continuous in the interval [0,2] as the functions is quadratic and we can conclude that from its graph
also the f(x) is differentiable in (0,2)
f'(x) = 6x - 2
Now the function satisfies both the conditions
so applying MVT
6x-2 = f(2) - f(0) / 2-0
6x-2 = 9 - 1 /2
6x-2 = 4
6x=6
x=1
so this is the tangent line for this given function.
7ab a - b
-------------- - --------------
a^2 - b^2 a + b
7ab a - b
= -------------- - --------------
(a-b)(a+b) a + b
7ab (a - b)^2
= -------------- - -----------------------
(a-b)(a+b) (a + b)(a-b)
7ab a^2 - 2ab + b^2
= -------------- - -----------------------
(a-b)(a+b) (a + b)(a-b)
7ab - a^2 + 2ab - b^2
= -----------------------------------
(a-b)(a+b)
- a^2 + 9ab - b^2
= -----------------------------------
(a-b)(a+b)
Answer is A. first one
Answer:
The answer I think is 32
Step-by-step explanation:
47-15=32
32
47-
15