All categories

3 years ago

The mass of a car tire is 17.25 kilograms. What is the mass of a car tire in grams?

Mathematics

1 answer:

nika2105 [10]3 years ago

4 0

Answer:

17,250

Step-by-step explanation:

since there are 1000 grams for each kilogram

You might be interested in

On Saturday, mason biked 1.5 hours at a speed of 11.9 miles per hour. on Sunday, he biked 3.2 hours at a speed of 14.8 miles per

solniwko [45]

1.7 miles: subtract 1.5 from 3.2 which equals 1.7 (make sure to line up the decimals!)

3 0

3 years ago

Which fraction is greater than 3 + 1/2 - 55/8 or 7/8

Mila [183]

7/8 is ur answer because
it can be cut into smaller parts

8 0

2 years ago

what is the least possible value of the smallest of 99 consecutive positive integers whose sum is a perfect cube

Dmitrij [34]

Let the least possible value of the smallest of 99 cosecutive integers be x and let the number whose cube is the sum be p, then

$\frac{99}{2} (2x+98)=p^3 \\ \\ 99x+4,851=p^3\\ \\ \Rightarrow x=\frac{p^3-4,851}{99}$

By substitution, we have that $p=33$ and $x=314$ .

Therefore, <span>the least possible value of the smallest of 99 consecutive positive integers whose sum is a perfect cube is 314.</span>

3 0

3 years ago

3x3-5/5x6+19 i don’t know what I’m don’t wrong

KonstantinChe [14]

Hi there!

For these two equations, we would be using PEMDAS...

$3$ · $3=9-5=4$

$5$ · $6=30+19=49$

Hope this helps!

4 0

3 years ago

If a = √3-√11 and b = 1 /a, then find a² - b²

Serga [27]

If $b=\frac1a$ , then by rationalizing the denominator we can rewrite

$b = \dfrac1{\sqrt3-\sqrt{11}} \times \dfrac{\sqrt3+\sqrt{11}}{\sqrt3+\sqrt{11}} = \dfrac{\sqrt3+\sqrt{11}}{\left(\sqrt3\right)^2-\left(\sqrt{11}\right)^2} = -\dfrac{\sqrt3+\sqrt{11}}8$

Now,

$a^2 - b^2 = (a-b) (a+b)$

and

$a - b = \sqrt3 - \sqrt{11} + \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{9\sqrt3 - 7\sqrt{11}}8$

$a + b = \sqrt3 - \sqrt{11} - \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{7\sqrt3 - 9\sqrt{11}}8$

$\implies a^2 - b^2 = \dfrac{\left(9\sqrt3 - 7\sqrt{11}\right) \left(7\sqrt3 - 9\sqrt{11}\right)}{64} = \boxed{\dfrac{441 - 65\sqrt{33}}{32}}$

5 0

1 year ago