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strojnjashka [21]
3 years ago
9

Does anyone minding helping me with exterior angles ? due in 2 days

Mathematics
2 answers:
Darya [45]3 years ago
8 0

Answer:

see explanation

Step-by-step explanation:

The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.

∠ CBD is an exterior angle of the triangle, then

6x = x + 40 + 3x + 10, that is

6x = 4x + 50 ( subtract 4x from both sides )

2x = 50 ( divide both sides by 2 )

x = 25

Thus

∠ CBD = 6x = 6 × 25 = 150°

∠ CBA and ∠ CBD are adjacent angles and supplementary, sum to 180°, then

150° + ∠ CBA = 180° ( subtract 150° from both sides )

∠ CBA = 30°

Goryan [66]3 years ago
5 0

Answer:

x=25

Step-by-step explanation:

(x+40)+(3x+10)=6x

4x+50=6x

50=2x

25=x

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PLEASE HELP!!!!!! The line of symmetry for the quadratic equation y = ax 2 - 8x - 3 is x = 2. What is the value of "a"?
nataly862011 [7]
y= ax^{2} -8x-3

1.

the line of symmetry is x=2, means that the x coordinate of the vertex is x=2.

the point x=2 is the midpoint of the roots x_1 and x_2. 

so 
\frac{x_1+x_2}{2}=2

x_1+x_2=4

Remark: in the x-axis, if c is the midpoint of a and b, then c= \frac{a+b}{2}


2.
since x_1 and x_2 are roots 

a(x_1)^{2} -8(x_1)-3=0 and a(x_2)^{2} -8(x_2)-3=0

3.
equalizing:

a(x_1)^{2} -8(x_1)-3=a(x_2)^{2} -8(x_2)-3

a(x_1)^{2} -8(x_1)=a(x_2)^{2} -8(x_2)

a(x_1)^{2}-a(x_2)^{2} =8(x_1) -8(x_2)

in the left side factorize a, in the left side factorize 8:

a[(x_1)^{2}-(x_2)^{2}] =8(x_1 -x_2)

in the right side use the difference of squares formula:

a(x_1 -x_2)(x_1 +x_2) =8(x_1 -x_2)

simplify by (x_1 -x_2)

a(x_1 +x_2) =8

substitute (x_1 +x_2) with 4:

a*4 =8

a=2


Answer: C)2

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4 years ago
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8 0
3 years ago
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inn [45]
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Answer:

35 two pointers, 18 one pointers

Step-by-step explanation:

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