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frez [133]
3 years ago
11

When Hana goes to the mall, she always buys the same lunch and also buys some books. The table shows the number of books she buy

s, x, and the total amount of money she spends, y.
x 1 2 3 4 5
y 17 21 23 26 34
If this data were displayed in a scatter plot, select ALL statements that would be true about a good trend line summarizing the data.

Group of answer choices

The slope approximates the cost of Hana's lunch.

The y-intercept approximates the average cost of one book.

The y-intercept approximates the cost of Hana's lunch.

The slope approximates the average cost of one book.

The trend line goes through the origin.
Mathematics
2 answers:
Lera25 [3.4K]3 years ago
6 0

Answer:

positive

Step-by-step explanation:

ong no cap

Zarrin [17]3 years ago
4 0

Answer:

positive and d

Step-by-step explanation:

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(

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AlexFokin [52]

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<h2>258</h2>

258\quad \mathrm{Remainder}\quad \:0

Step-by-step explanation:

\frac{1032}{4} \\\\\begin{matrix}4\overline{|\smallspace1032}\space\space\space\space\space\space\space\space\space\space\space\space\end{matrix}\\\\\mathrm{Divide}\:10\:\mathrm{by}\:4\:\mathrm{to\:get}\:2\\\begin{matrix}\space\space\space\space\space\space\emptyspace2\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\\ 4\overline{|\smallspace1032}\space\space\space\space\space\space\space\space\space\space\space\space\end{matrix}\\\\

\mathrm{Multiply\:the\:quotient\:digit}\:\left(2\right)\:\mathrm{by\:the\:divisor}\:4\\\begin{matrix}\space\space\space\space\space\space\emptyspace2\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\\4\overline{|\smallspace1032}\space\space\space\space\space\space\space\space\space\space\space\space\\ \space\space\space\space\space\space\underline{\emptyspace8}\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\space\end

Long story short ,

\mathrm{The\:solution\:for\:Long\:Division\:of}\:\\\frac{1032}{4}\:\mathrm{is}\\\:258\:\mathrm{with\:remainder\:of}\:0

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