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r-ruslan [8.4K]
2 years ago
11

Someone help me pls ill give brainlist to the correct one

Mathematics
1 answer:
jek_recluse [69]2 years ago
4 0

Answer:

the answer I got was

\frac{6}{10} or \:  \frac{3}{5}

Step-by-step explanation:

so I included a picture of my work

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If the cow can't ran over the car?
adell [148]
Lol what I don't understand what u are asking
8 0
3 years ago
For each part of this problem, show all your work and write a probability statement.
AlladinOne [14]

Answer:

Follows are the answer to the given point.

Step-by-step explanation:

In point 1:

\to P( \text{number of response}) = \frac{192}{338} \\

                                        = \frac{96}{169}\\\\= 0.56

In point 2:

\to P| \text{(Zoloft and fill response)}| = \frac{27}{338}

                                                 = 0.079

In point 3:

\to P(\frac{\text{ full or partial}}{\text{St. John's Wort}}) = \frac{\frac{43}{338}}{\frac{113}{338}}

                                = \frac{43}{338} \times \frac{338} {113}\\\\= \frac{43}{113}\\\\= 0.38

In point 4:

\to P(\frac{\text{Placebo}}{\text{full or response}}) = P(\frac{(\text{Placebo} \cap \text{full or response})} {\text{p(full response)}})

                               = \frac{\frac{79}{338}}{ 1- \frac{91}{338}} \\\\ = \frac{\frac{79}{338}}{  \frac{338-91}{338}} \\\\  = \frac{\frac{79}{338}}{\frac{247}{338}} \\\\  = \frac{79}{338} \times \frac {338}{247} \\\\= \frac{79}{274} \\\\ = 0.28

4 0
3 years ago
Find the value of x.<br> 95°<br> (7x – 40°<br> (3x + 23)<br> (9x – 6)°
BaLLatris [955]

Answer:10x

Step-by-step explanation:

yes

7 0
2 years ago
It is believed that Lake Tahoe Community College (LTCC) Intermediate Algebra students get less than seven hours of sleep per nig
Kitty [74]

Answer: No , at 0.05 level of significance , we have sufficient evidence to reject the claim that LTCC Intermediate Algebra students get less than seven hours of sleep per night, on average.

Step-by-step explanation:

Let \mu denotes the average hours of sleep per night.

As per given , we have

H_0:\mu=7\\H_a:\mu

, since H_a is left-tailed and population standard deviation is unknown, so the test is a left-tailed t -test.

Also , it is given that ,

Sample size : n= 22

Sample mean : \overline{x}=7.24

Sample  standard deviation : s= 1.93

Test statistic : t=\dfrac{\overline{x}-\mu}{\dfrac{s}{\sqrt{n}}}

i.e.  t=\dfrac{7.24-7}{\dfrac{1.93}{\sqrt{22}}}\approx0.58

For significance level \alpha=0.05 and degree of freedom 21 (df=n-1),

Critical t-value for left-tailed test= t_{\alpha, df}=t_{0.05,21}=- 1.7207

Decision : Since the test statistic value (0.58) > critical value  1.7207, it means we are failed to reject the null hypothesis .

[Note : When |t_{cal}|>|t_{cri}|, then we accept the null hypothesis.]

Conclusion: We have sufficient evidence to reject the claim that LTCC Intermediate Algebra students get less than seven hours of sleep per night, on average.

6 0
2 years ago
Chapter 15 probability
denpristay [2]
What do you mean by that? 
4 0
3 years ago
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