M=dc/dp=4/6=4/6=2/3
c(p)=2p/3 +b using (6,4)
4=2(6)/3+b
4=4+b, b=0 so
c(p)=2p/3
(the number of cherries needed as a function of the number of pies)
there are 360 degrees in a complete circle
360/18 = 20
so the answer is C
Answer:
The required vector parametric equation is given as:
r(t) = <3cost, 3sint>
For 0 ≤ t ≤ 2π
Step-by-step explanation:
Given that
f(x, y) = <2y, -sin(y)>
Since C is a cirlce centered at the origin (0, 0), with radius r = 3, it takes the form
(x - 0)² + (y - 0)² = r²
Which is
x² + y² = 9
Because
cos²β + sin²β = 1
and we want to find a vector parametric equations r(t) for the circle C that starts at the point (3, 0), we can write
x = 3cosβ
y = 3sinβ
So that
x² + y² = 3²cos²β + 3²sin²β
= 9(cos²β + sin²β) = 9
That is
x² + y² = 9
The vector parametric equation r(t) is therefore given as
r(t) = <x(t), y(t)>
= <3cost, 3sint>
For 0 ≤ t ≤ 2π
2x^4
13b-10
5y+10
5a^3
2b^2+8a