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hram777 [196]
3 years ago
14

Combine the like terms to create an equivalent expression: 8t+1+(-4t)+(-6)

Mathematics
2 answers:
Inessa [10]3 years ago
8 0

Answer:

you will get the answer 4t-5

plz mark as brainliest

MaRussiya [10]3 years ago
7 0
Pretty sure it’s 4t+-5
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Answer:

29

Step-by-step explanation:

4x+(x+35)=180

5x+35=180

5x=145

x=29

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I dont understand this
Reil [10]
U basically solve: (4sqrt8)*2 + (5 sqrt 12 + 6 sqrt 20)*2
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Help me. Please due today
Schach [20]

Answer:

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Step-by-step explanation:

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2 years ago
Please help me on this problem
Anna71 [15]

Answer:

The pairs of integer having two real solution forax^{2} -6x+c = 0 are

  1. a = -4, c = 5
  2. a = 1, c = 6
  3. a = 2, c = 3
  4. a = 3, c = 3

Step-by-step explanation:

Given

ax^{2} -6x+c = 0

Now we will solve the equation by putting all the 6 pairs so we get the  following

-3x^{2} -6x-5 = 0 for a = -3 , c=-5

-4x^{2} -6x+5 = 0 for a = -4 , c=5

1x^{2} -6x+6 = 0 for a = 1 , c=6

2x^{2} -6x+3 = 0 for a = 2 , c=3

3x^{2} -6x+3 = 0 for a = 3 , c=3

5x^{2} -6x+4 = 0 for a = 5 , c=4

The above  all are Quadratic equations inn general form ax^{2} +bx+c=0

where we have a,b and c constant values

So for a real Solution we must have

Disciminant , b^{2} -4\timesa\timesc \geq 0

for a = -3 , c=-5 we have

Discriminant =-24 which is less than 0 ∴ not a real solution.

for a = -4 , c=5 we have

Discriminant = 116 which is greater than 0 ∴ a real solution.

for a = 1 , c=6 we have

Discriminant =12 which is greater than 0 ∴ a real solution.

for a = 2 , c=3 we have

Discriminant =12 which is greater than 0 ∴ a real solution.

for a = 3 , c=3 we have

Discriminant =0 which is equal to 0 ∴ a real solution.

for a = 5 , c=4 we have

Discriminant =-44 which is less than 0 ∴ not a real solution.

7 0
3 years ago
Help! Need by 10:30 to turn in and I'm confused!
JulsSmile [24]

Answer:

21.97 tissues

15.47 cough drops

Step-by-step explanation:

13x1.69=21.97

1.19x15.47

7 0
3 years ago
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