Solve the equation n + 75 = 155

What is the y-intercept of f(x) =(3/5) ^x

allsm [11]

Answer:

(0, 1 )

Step-by-step explanation:

To find the y- intercept, that is where the function crosses the y- axis.

At this point the x- coordinate is zero.

Substitute x = 0 into the function, that is

f(0) = $(3/5)^{0}$ = 1 ← y - intercept

6 0

4 years ago

Yo how is the answer

seraphim [82]

Answer:

I think it's 18 but I'm not sure

6 0

3 years ago

Line segment AB was translated 2 units right and 7 units down to create line segment CD. A transversal intersects the two line s

belka [17]

These are correct statements:

- Line segments AB and CD are parallel.

- Since ∠1 and ∠3 are corresponding angles, they are congruent.
These are incorrect statements:

- Since ∠3 and ∠4 are corresponding angles, they are congruent. They are not corresponding angles, they are supplementary meaning they, together, equal 180.

- Since ∠1 and ∠2 are corresponding angles, they are congruent. These are also not corresponding, they are supplementary.

- Line segments AB and CD are perpendicular. They are not crossing over each other.

- Since ∠1 and ∠4 are alternate interior angles, they are congruent. They are not corresponding, they are supplementary. ∠1 and ∠3 are corresponding just like ∠2 and ∠4.

6 0

3 years ago

Divide: 782 ÷ 12 A) 65 R2 B) 65 C) 70 R5 D) 74

serious [3.7K]

It would be A i just did the math

5 0

3 years ago

Read 2 more answers

P(X< ) 1-P(X> ) A softball pitcher has a 0.626 probability of throwing a strike for each curve ball pitch. If the softball

Mashutka [201]

Answer:

19.49% probability that no more than 16 of them are strikes

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .