The first equation
6x^2 -18x-24=0
-the graph opens up
6(x^2 -3x -4)=0
6(x^2 -3x +9/4-4-9/4)=0
6(x-3/2)-25x6/4=
6(x-3/2)-75/2
-Vertex is at (3/2, -75/2)
-Axis of symmetry is x=3/2
Second equation
3r^2 -16r -12=0
-the graph opens up
...
Only selections B and D give a maximum height of 13 at t=3. However, both of those functions have the height be -5 at t=0, meaning the ball was served from 5 ft below ground. This does not seem like an appropriate model.
We suspect ...
• the "correct" answers are probably B and D
• whoever wrote the problem wasn't paying attention.
Answer:
1 2/7
Step-by-step explanation:
4.5:3 1/2
45/10 ÷ 7/2
45/10 x 2/7
90/70=9/7
=1 2/7
Answer:
7(6m - 4) = -364
multiply 7 for both variables in the parenthesis
42m - 28 = -364
move 28 to other side
42m= -336
divide 42 on both sides
m= -8
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