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Salsk061 [2.6K]
3 years ago
15

How many different numbers are possible?

Mathematics
1 answer:
Artyom0805 [142]3 years ago
8 0

Each of the first 3 letters can be chosen from the 23 letters, {A, B, C, …, U, V, W}, so there are 23³ possible choices.

The first 2 digits can be any number from {0, 1, 2, …, 9}, so there are 10² choices.

The last digit cannot be 0 or 9, so you can select from {1, 2, 3, …, 8} which gives 8 choices.

Then the total number of PINs that you can make is

23³ × 10² × 8 = 9,733,600

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Answer:

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Step-by-step explanation:

solution

let the length of sides of isosceles triangle is = x

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base  = x -3 ( as it is 3 m smaller in length )

according to formula of perimeter of isosceles triangle

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dividing both sides by 3

15.6/3 = 3(x-1)/3

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so length of sides is 6 .2 m ( other side will also be 6.2 m)

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4 years ago
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hope this helps
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