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Salsk061 [2.6K]
3 years ago
15

How many different numbers are possible?

Mathematics
1 answer:
Artyom0805 [142]3 years ago
8 0

Each of the first 3 letters can be chosen from the 23 letters, {A, B, C, …, U, V, W}, so there are 23³ possible choices.

The first 2 digits can be any number from {0, 1, 2, …, 9}, so there are 10² choices.

The last digit cannot be 0 or 9, so you can select from {1, 2, 3, …, 8} which gives 8 choices.

Then the total number of PINs that you can make is

23³ × 10² × 8 = 9,733,600

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Detailed Answer:

An algebraic equation can be defined as a mathematical statement in which two expressions are set equal to each other.

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4 years ago
How can I solve this equation 5x^2-2x-6=-2x^2+9x
wel
Add 2x^2 to both sides
7x^2-2x-6=9x

Subtract 9x from both sides
7x^2-11x-6=0

Factor by using slip and slide
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Then use the Zero Product Property to find roots
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Final answer: x=-3/7, x=2
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I don’t get that because I bend more information
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