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elixir [45]
3 years ago
9

If the correlation coefficient between two variables is .90, what percent of the variance is explained by this correlation

Mathematics
1 answer:
ZanzabumX [31]3 years ago
5 0

Answer:  81% of the variance in dependent variable is explained by this correlation .

Step-by-step explanation:

For X = Independent variable and Y=dependent variable,

If r= correlation coefficient , then we say r^2<em>  </em>of the<em> </em>variance in Y is explained by Variable X.

Given: r= 0.90

(0.90)^2= 0.81

So, 81% of the variance in dependent variable is explained by this correlation .

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30 POINTS PLS HELP
zysi [14]

Answer:

We proceed to use the following operations: (i) <em>Vertical translation downwards</em> (k = -\frac{1}{2}), (ii) <em>Vertical compression</em> (c = \frac{1}{2}), (iii) <em>Vertical translation upwards</em> (k = \frac{1}{2}). The graph is presented below.

Step-by-step explanation:

To transform y = \frac{5}{4}\cdot x + \frac{1}{2} into y = \frac{5}{8}\cdot x + \frac{1}{2}, we apply the following steps:

(i) <em>Vertical translation downwards</em> (k = -\frac{1}{2})

g(x) = f(x) +k (1)

(ii) <em>Vertical compression</em> (c = \frac{1}{2})

g(x) = c\cdot f(x) (2)

(iii) <em>Vertical translation upwards</em> (k = \frac{1}{2})

g(x) = f(x) + k

Now, we proceed to transform the primitive expression:

Step 1

f'(x) = \frac{5}{4}\cdot x

Step 2

f''(x) = \frac{5}{8}\cdot x

Step 3

g(x) = \frac{5}{8}\cdot x + \frac{1}{2}

The graph of both function are now presented below. The parent function is the red line and the new function is represented by the blue line.

7 0
3 years ago
A+B = ?<br>A.257<br>B.267<br>C.524<br>D.526​
SVEN [57.7K]

Answer:

C. 524.

Step-by-step explanation:

a=0.5(251+263)=257;

b=0.5*(263+271)=267;

a+b=257+267=524.

8 0
3 years ago
A random sample of 700 home owners in a particular city found 112 home owners who had a swimming pool in their backyard. Find a
vekshin1

Answer: (13.28\%,\ 18.72\%)

Step-by-step explanation:

Given : A random sample of 700 home owners in a particular city found 112 home owners who had a swimming pool in their backyard.

i.e. n= 700 and x= 112

Sample proportion : \hat{p}=\dfrac{x}{n}=\dfrac{112}{700}=0.16

z-value for 95% confidence interval : z_c=1.960

Now, the 95% confidence interval for the true percent of home owners in this city who have a swimming pool in their backyard will be :-

\hat{p}\pm z_c\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

=0.16\pm (1.96)\sqrt{\dfrac{0.16(1-0.16)}{700}}

=0.16\pm (1.96)(0.013856)\\\\\approx 0.16\pm0.0272\\\\ =(0.16-0.0272,\ 0.16+0.0272)=(0.1328,\ 0.1872)=(13.28\%,\ 18.72\%)

Hence, 95% confidence interval for the true percent of home owners in this city who have a swimming pool in their backyard : (13.28\%,\ 18.72\%)

6 0
3 years ago
Jody has 4 red marbles, 7 blue marbles, and 9 yellow marbles. What is the ratio of red marbles to blue marbles?
xxTIMURxx [149]
The answer is C. 4:20
Hope that helps!

5 0
3 years ago
Read 2 more answers
It+is+said+60%+of+families+own+a+pet. +of+a+sample+of+95+families,+70+owned+pets. +perform+a+hypothesis+test+to+determine+whethe
viktelen [127]

There is sufficient evidence to conclude that, the percentage of the families who own a pet is different than 60%.

<h3>What are null hypotheses and alternative hypotheses?</h3>

In null hypotheses, there is no relationship between the two phenomena under the assumption that it is not associated with the group. And in alternative hypotheses, there is a relationship between the two chosen unknowns.

It Is said That 60% of families own a pet.

Of a sample of 95 families, 70 owned pets.

Whether the percent of families who own pets is different than 60%.

Let P be a proportion of the family who owns pets

Then by the test, we have

H₀: P = 0.60

Hₐ: P ≠ 60

Then by the test statistic, we have

z_o = \dfrac{\bar{P} - P_o}{\sqrt{\dfrac{P_o(1 - P_o)}{n}}}

Where

\bar P  = sample proportion

P₀ = hypothesis proporion

n = sample size

Then we have

\bar P = x/n

\bar P = 70/95

\bar P = 0.74

Then the test statistic will be

z_o = \dfrac{0.74-0.60}{\sqrt{\dfrac{0.60(1-0.60)}{95}}}

z₀ = 2.785

Then the critical region will be

Critical value = ± z_{\alpha /2}

α = 0.05

α/2 = 0.025

Then we have

z₀.₀₂₅ = 1.96

Then the critical value will be

Critical value = ± 1.96

We reject if |z_o| > |z_{\alpha /2}|

We have

|z_o| > |z_{\alpha /2}|\\

2.79 > 1.96

We reject the null hypothesis at a 5% significance level.

There is sufficient evidence to conclude that, the percentage of the families who own a pet is different than 60%.

More about the null hypotheses and alternative hypotheses link is given below.

brainly.com/question/9504281

#SPJ4

6 0
2 years ago
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