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krok68 [10]
3 years ago
6

(z^6/z)^2 QUICK ILL GIVE BRANLIEST

Mathematics
1 answer:
defon3 years ago
7 0

Answer,  z10

Step-by-step explanation:

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Solve the equation uding the most direct method: 3x(x+6)=-10?​
Tanzania [10]

To solve this problem, you will use the distributive property to create an equation that can be rearranged and solved using the quadratic formula.

<h3>Distribute</h3>

Use the distributive property to distribute 3x into the term (x + 6):

3x(x+6)=-10

3x^2+18x=-10

<h3>Rearrange</h3>

To create a quadratic equation, add 10 to both sides of the equation:

3x^2+18x+10=-10+10

3x^2+18x+10=0

<h3>Use the Quadratic Formula</h3>

The quadratic formula is defined as:

\displaystyle x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

The model of a quadratic equation is defined as ax² + bx + c = 0. This can be related to our equation.

Therefore:

  • a = 3
  • b = 18
  • c = 10

Set up the quadratic formula:

\displaystyle x=\frac{-18 \pm \sqrt{(18)^2 - 4(3)(10)}}{2(3)}

Simplify by using BPEMDAS, which is an acronym for the order of operations:

Brackets

Parentheses

Exponents

Multiplication

Division

Addition

Subtraction

Use BPEMDAS:

\displaystyle x=\frac{-18 \pm \sqrt{324 - 120}}{6}

Simplify the radicand:

\displaystyle x=\frac{-18 \pm \sqrt{204}}{6}

Create a factor tree for 204:

204 - 1, 2, 3, 4, 6, 12, 17, 34, 51, 68, 102 and 204.

The largest factor group that creates a perfect square is 4 × 51. Therefore, turn 204 into 4 × 51:

\sqrt{4\times51}

Then, using the Product Property of Square Roots, break this into two radicands:

\sqrt{4} \times \sqrt{51}

Since 4 is a perfect square, it can be evaluated:

2 \times \sqrt{51}

To simplify further for easier reading, remove the multiplication symbol:

2\sqrt{51}

Then, substitute for the quadratic formula:

\displaystyle x=\frac{-18 \pm 2\sqrt{51}}{6}

This gives us a combined root, which we should separate to make things easier on ourselves.

<h3>Separate the Roots</h3>

Separate the roots at the plus-minus symbol:

\displaystyle x=\frac{-18 + 2\sqrt{51}}{6}

\displaystyle x=\frac{-18 - 2\sqrt{51}}{6}

Then, simplify the numerator of the roots by factoring 2 out:

\displaystyle x=\frac{2(-9 + \sqrt{51})}{6}

\displaystyle x=\frac{2(-9 - \sqrt{51})}{6}

Then, simplify the fraction by reducing 2/6 to 1/3:

\boxed{\displaystyle x=\frac{-9 + \sqrt{51}}{3}}

\boxed{\displaystyle x=\frac{-9 - \sqrt{51}}{3}}

The final answer to this problem is:

\displaystyle x=\frac{-9 + \sqrt{51}}{3}

\displaystyle x=\frac{-9 - \sqrt{51}}{3}

3 0
2 years ago
What is x in this problem? someone please help
Vedmedyk [2.9K]
X=21
This is because both of those angles are equal, so you would divide 42 by 2 and get 21
7 0
3 years ago
What is the solution
bonufazy [111]
You would have to square root both sides in order to get a solution, and you can't have a negative under the radical unless you plan to do imaginary numbers, and I don't see imaginary numbers as part of your answers, so the answer in this case would be F, no solution
6 0
3 years ago
Help me please :( please
natta225 [31]
Please note that if you mult. 243 by 2/3, you get 162.
If you mult. 162 by 2/3, you get 108.
If you mult. 108 by 2/3, you get 72.

We can then safely conclude that the common ratio is 2/3.

Our last given set member was 72.  
Mult. this by 2/3 to get the 5th member:  48.
Mult. this 48 by 2/3 to get the 6th member:  32.
Mult. this 32 by 2/3 to get the 7th and last desired member:  21 1/3
7 0
3 years ago
Which graph represents y=sin x° for 0&lt;x°&lt;360°?
Ilya [14]

sin 0 = 0

sin 90 = 1

sin 180 = 0

sin 270 = -1

sin 360 = 0

So its Graph C.

4 0
3 years ago
Read 2 more answers
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