Answer:
Σ(-1)^kx^k for k = 0 to n
Step-by-step explanation:
The nth Maclaurin polynomials for f to be
Pn(x) = f(0) + f'(0)x + f''(0)x²/2! + f"'(0)x³/3! +. ......
The given function is.
f(x) = 1/(1+x)
Differentiate four times with respect to x
f(x) = 1/(1+x)
f'(x) = -1/(1+x)²
f''(x) = 2/(1+x)³
f'''(x) = -6/(1+x)⁴
f''''(x) = 24/(1+x)^5
To calculate with a coefficient of 1
f(0) = 1
f'(0) = -1
f''(0) = 2
f'''(0) = -6
f''''(0) = 24
Findinf Pn(x) for n = 0 to 4.
Po(x) = 1
P1(x) = 1 - x
P2(x) = 1 - x + x²
P3(x) = 1 - x+ x² - x³
P4(x) = 1 - x+ x² - x³+ x⁴
Hence, the nth Maclaurin polynomials is
1 - x+ x² - x³+ x⁴ +.......+(-1)^nx^n
= Σ(-1)^kx^k for k = 0 to n
I think this quisthionbchk shjvsjjwv hsjvsbkzbxbs hhsvsvwjkwvs hskvsvdod
Answer:
I don't really know so sorry about that.
Step-by-step explanation:
The function’s value when x = −1 will be C. g(−1) = 1.
<h3>How to calculate the value of the function?</h3>
It should be noted that that a function is simply used to show the relationship that exists between the variables.
There's a 2-column table with 5 rows. The first column is labeled g of x with entries negative 3, negative 2, 0, 2, 3. The second column is labeled f of x with entries.
The. function is x³ + 6x² + 12x + 8.
= x³ + 6x² + 12x + 8.
= (-1)³ + 6(-1)² + 12(-1) + 8
= -1 + 6 - 12 + 8
= 1
Therefore, the correct option is C.
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