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PIT_PIT [208]
2 years ago
14

Solve 3x-4=17 you may use the flowchart to help if u wish

Mathematics
1 answer:
Neko [114]2 years ago
8 0

Answer:

3x-4=17

3x=17+4

3x=21

x=21/3

x=7

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3 years ago
If a+b+c =0 show that a³+b³+c³= 3abc
slega [8]

Answer:

Step-by-step explanation:

a+b+c=0, a+b=-c,a+c=-b, b+c=-a

(a+b+c)^3=(a+b+c)^2*(a+b+c)=(a^2+b^2+c^2+2ab+2ac+2bc)*(a+b+c)=

a^3+ab^2+ac^2+2a^2b+2a^2c+2abc+a^2b+b^3+bc^2+2ab^2+2abc+2b^2c+a^2c+b^2c+c^3+2abc+2ac^2+2bc^2=a^3+b^3+c^3+3a^2b+3a^2c+3ac^2+3ab^2+3bc^2+3b^2c+6abc=

a^3+b^3+c^3+3a^2*(b+c)+3c^2(a+b)+3b^2(a+c)+6abc=

a^3+b^3+c^3+3a^2*(-a)+3c^2*(-c)+3b^2*(-b)+6abc=

a^3+b^3+c^3-3a^3-3c^3-3b^3+6abc=

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3 years ago
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Step-by-step explanation:

You must first add 20 to all inqualies, leaving u with 0 is greater than or equal to 2x which is also greater than or equal to 40.

Divde everything by 2 to get rid of the 2 from the x

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Thats the answers

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