Now, the cosecant of θ is -6, or namely -6/1.
however, the cosecant is really the hypotenuse/opposite, but the hypotenuse is never negative, since is just a distance unit from the center of the circle, so in the fraction -6/1, the negative must be the 1, or 6/-1 then.
we know the cosine is positive, and we know the opposite side is -1, or negative, the only happens in the IV quadrant, so θ is in the IV quadrant, now
recall that
therefore, let's just plug that on the remaining ones,
now, let's rationalize the denominator on tangent and secant,
This problem mean you have to find the point that the Domain and Range is suit (I'm sorry English is my second language)
Example:
1) G ; 2) Y
If you want me to do the rest of it tell me Okay ^^
Answer: Option C is correct
Step-by-step explanation:
We know tha tCos(A-B) = cosA cosB + sinAsinB
Plugging A = 180 and B = Ф
cos(180-Ф)= cos180cosФ+sin180sinФ
= (-1) cosФ+ (0) sinФ [ since cos180=-1 and sin180 =0]
= -cosФ + 0
= -cosФ
Therefore option C is the correct answer.
Answer:
I think steven paid 50,000 dollars in total
Step-by-step explanation: