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3 years ago

9

In the straightedge and compass construction of the equilateral triangle

1 answer:

Shtirlitz [24]3 years ago

5 1

The answer is C, AB and BC are both radii of Circle B. You can tell by the way both lines come from the center of Circle B to the edge. AC is not a radii of Circle B, and AC is also not in the question.

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I need to know what is in the blank space ?

Ber [7]

There is nothing in the space. If there were, then the space would not be blank.

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3 years ago

97 term of-5,-23,-41

Wewaii [24]

Answer:

-1147

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Help please thank you!! :)

tankabanditka [31]

Answer:

Area of circle: 1662.57 cm

Circumference of circle: 144.57 cm

Step-by-step explanation:

Formula of area of circle:

pi x r2 or radius x radius

So, it's 22/7 x 23 x 23 = 1662.571429

Formula of circumference of circle:

2 x pi x radius OR

pi x diameter

Let's use the second method, to find diameter it is radius x 2 = 46

So,

46 x 22/7 = 144.5714286

4 0

3 years ago

Convert the Cartesian equation x^2 + y^2 = 16 to a polar equation.

RideAnS [48]

Answer:

Problem 1: $r=4$

Problem 2: $r=-2\sin(\theta)$

Problem 3: $r\sin(\theta)=3$

Step-by-step explanation:

Problem 1:

So we are going to use the following to help us:

$x=r \cos(\theta)$

$y=r \sin(\theta)$

$\frac{y}{x}=\tan(\theta)$

So if we make those substitution into the first equation we get:

$x^2+y^2=16$

$(r\cos(\theta))^2+r\sin(\theta))^2=16$

$r^2\cos^2(\theta)+r^2\sin^2(\theta)=16$

Factor the $r^2$ out:

$r^2(\cos^2(\theta)+\sin^2(\theta))=16$

The following is a Pythagorean Identity: $\cos^2(\theta)+\sin^2(\theta)=1$ .

We will apply this identity now:

$r^2=16$

This implies:

$r=4 \text{ or } r=-4$

We don't need both because both of include points with radius 4.

Problem 2:

$x^2+y^2+2y=0$

$(r\cos(\theta))^2+(r\sin(\theta))^2+2(r\sin(\theta))=0$

$r^2\cos^2(\theta)+r^2\sin^2(\theta)+2r\sin(theta)=0$

Factoring out $r^2$ from first two terms:

$r^2(\cos^2(\theta)+\sin^2(\theta))+2r\sin(\theta)=0$

Apply the Pythagorean Identity I mentioned above from problem 1:

$r^2(1)+2r\sin(\theta)=0$

$r^2+2r\sin(\theta)=0$

or if we factor out r:

$r(r+2\sin(\theta))=0$

$r=0 \text{ or } r=-2\sin(\theta)$

r=0 is actually included in the other equation since when theta=0, r=0.

Problem 3:

$y=3$

$r\sin(\theta)=3$

8 0

4 years ago

Give an example of repeating, nonterminating non-integers

Goshia [24]

I know non terminating decimals but not integers

8 0

3 years ago