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3 years ago

8

Douglas wrapped the pots for flowers in colored foil. He wrapped 6 lily pots, 7 daffodil pots, and 4 hydrangea pots. If Douglas

only wrapped one pot in green foil, what is the probability he wrapped the pot of a lily in green foil?
A. 7/13

B. 1/6

C.6/17

D. 1/2

1 answer:

PIT_PIT [208]3 years ago

7 0

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Due to a leak, the amount of water in a pool is decreasing by 5858 gal every hour. What is the total change in the number of gal

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Answer:

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3 years ago

SAT reading and writing section scores of a random sample of twenty 11th-grade students in a certain high school are given below

kvasek [131]

Answer:

The value of test statistics is 25.

Step-by-step explanation:

We are given below the SAT reading and writing section scores of a random sample of twenty 11th-grade students in a certain high school;

380, 520, 480, 510, 560, 630, 670, 490, 500, 550, 400, 350, 440, 490, 620, 660, 700, 730, 740, 560

<em>Let </em> $\sigma$ <em> = population standard of the reading and writing section SAT score of the students in this school</em>

So, Null Hypothesis, $H_0$ : $\sigma \leq$ 100 {means that the reading and writing section SAT score of the students in this school is lesser than or equal to 100}

Alternate Hypothesis, $H_A$ : $\sigma$ <em> </em>> 100 {means that the reading and writing section SAT score of the students in this school is higher than 100}

The test statistics that would be used here is <u>One-sample Chi-square</u> test statistics;

T.S. = $\frac{(n-1)s^{2} }{\sigma^{2} }$ ~ $\chi^{2} __n_-_1$

where, $s^{2}$ = sample variance = $\frac{\sum (X-\bar X)^{2} }{n-1}$ = 13135.8

n = sample of 11th-grade students = 20

So, <u><em>the test statistics</em></u> = $\frac{(20-1)\times 13135.8^{2} }{100^{2} }$

= 24.96 ≈ 25

Hence, the value of test statistics is 25.

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