Use the Pythagorean theorem!
This principle applies to any right triangles.
This states the relationship between the sides that
(7)² + (24)² = x²
All you have to do is simplify at this point.
49 + 576 = x²
625 = x²
√ √
x = 25
You should try to memorize this right triangle. It can be very helpful in fast questionnaires, such as the SAT.
The vertex point is (0,4)
The two other points are (-2,0)(2,0)
We know that the area of a circle in terms of π will be πr². However the area with respect to the diameter will be a different story. The first step here is to find a function relating the area and diameter of any circle --- ( 1 )
For any circle the diameter is 2 times the radius,
d = 2r
Therefore r = d / 2, which gives us the following formula through substitution.
A = π(d / 2)² = πd² / 4
<u>Hence the area of a circle as the function of it's diameter is A = πd² / 4. You can also say f(d) = πd² / 4.</u>
Now we can substitute " d " as 4, solving for the area ( A ) or f(4) --- ( 2 )
f(4) = π(4)² / 4 = 16π / 4 = 4π - <u>This makes the area of circle present with a diameter of 4 inches, 4π.</u>
Answer:
Step-by-step explanation:
192
We know that
in the first triangle
the ratio of the legs are
4.5/1.5-----> 3
then
case <span>A) 6 m and 2 m ------> ratio=6/3----> 3
so
</span><span>the legs of a second triangle are proportional to the lengths of the legs of the first triangle
</span>case B) 8 m and 5 m ------> ratio=8/5---->1.6
so
the legs of a second triangle are not proportional to the lengths of the legs of the first triangle
case C) 7 m and 3.5 mm ------> ratio=7/3.5---->2
so
the legs of a second triangle are not proportional to the lengths of the legs of the first triangle
case D) 10 m and 2.5 m ------> ratio=10/2.5---->4
so
the legs of a second triangle are not proportional to the lengths of the legs of the first triangle
case E) 11.25 m and 3.75 m ------> ratio=11.25/3.75---->3
so
the legs of a second triangle are proportional to the lengths of the legs of the first triangle
the answer is
A) 6 m and 2 m
E) 11.25 m and 3.75 m
