Hey there!
Let's plug in our values:
3(-2) - 4(1) =
-6-4 =
-10.
Hope this helps!
Given :
The percent of concentration of a certain drug in the bloodstream x hours after the drug is administered is given by
.
To Find :
Find the time at which the concentration is a maximum. b. Find the maximum concentration.
Solution :
For maximum value of x, K'(x) = 0.

Since, time cannot be negative, so ignoring x = -3 .
Putting value of x = 3, we get, K(3) = 15/( 9 + 9) = 5/6
Therefore, maximum value drug in bloodstream is 5/6 at time x = 3 units.
Hence, this is the required solution.
<em>1.) </em><em>3</em>
<em>Take the given equation </em>
<em>2y=6x-8</em>
<em>Now divide by 2 on each side</em>
<em>y=</em><em>3</em><em>x-4</em>
<em>Slope is </em><em>3</em>
<em>2.) y=1/3x-4</em>
Answer:
https://orion.math.iastate.edu/dept/links/formulas/form1.pdf
Step-by-step explanation: