The area of the circle is 16*16*pi=256pi. We can calculate 3/4 of the circle's area for the part not represented by the triangle and the shaded area, and then add in the triangle. 3/4 of the circle's area is 192pi.
The triangle is a right triangle with two legs of length 16. Therefore, it's area is 16*16/2=128, and the total area is 192pi+128, or 731.2.
Answer:
32
Step-by-step explanation:
Okay so first, the problem gives you the numbers to plug into the variables. So you see h=2 will be 2^2, because you plug it in. Now let me show you how I got the answer the Montana Way (Okay I know that sounds toooo cheesy)
12(3) - (2)^2
36 - 4
32
Answer:
c. 108.4
Step-by-step explanation:
cos theta = (u dot v)/ (||u|| ||v||)
where dot stands for dot product and || || is the magnitude
u = (1,5) v= (7,-4)
u dot v = (1*7 + 5*-4) = 7-20 = -13
||u|| = sqrt( 1^2 +5^2) = sqrt(1+25) = sqrt(26)
||v|| = sqrt(7^2 + (-4)^2) = sqrt(49+16) = sqrt(65)
cos theta = -13/ sqrt(26) sqrt(65)
cos theta = -13 /sqrt(1690)
theta = arccos (-13/sqrt(1690))
theta = 108.43