f(x)=9-2x
--------------------
f(x)=25
9-2x=25
-9 -9
-2x=16
/-2 /-2
x = -8
---------------------
f(x)=-41
9-2x=-41
-9 -9
-2x=-50
/-2 /-2
x = 25
----------------------
f(x)=17
9-2x=17
-9 -9
-2x=8
/-2 /-2
x = -4
-----------------------
f(x)=-8
9-2x=-8
-9 -9
-2x=-17
/-2 /-2
x = -17/2
Answer: option A. 9.2 gal/year
Justification:
The average rate of change from 1960 to 1970 is the change on the variable gallons consumed per passenger car divided by the period
average rate of change = Δg / Δt
Δg = 760 gallons - 668 gallons
Δt = 1970 year - 1960 year
760 gal - 668 gal 92 gal
average rate of change = -------------------------------- = ---------- = 9.2 gal / year
1970 year - 1960 year 10 year
Answer: 9.2 gal / year
As you see for this specific period, 1960 to 1970, the vehicles increased their consumption of gas per passenge, meaning that they became less efficient.
Answer:
3a-21
Step-by-step explanation:
You multiple 3 with the inside of the parenthesis. 3 time a = 3a and 3 times negative 7 is -21
4m+2 (m-5)=26
4m+2m-10=26
6m-10=26
6m=36
M=6
Answer:
3
Step-by-step explanation:
First multiply 1 by 2 and that equals 2. Then do 2 times .5 or 2 times 
. This is the same as finding the half of 2 that is 1. Therefore 1+2=3
