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3 years ago

15

Please help! I’ll mark brainlest :/

1 answer:

mafiozo [28]3 years ago

6 0

B. is the answer if you look closely

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Please help, any help would be appreciated.

k0ka [10]

Answer:

160,170 and 240,250

Step-by-step explanation:

sorry if wrong

3 0

2 years ago

Arrange the cones in order from lease volume to greatest volume

bearhunter [10]

Answer:

Volume of the cone in ascending order.

$V_{2}=270\pi\ units^{3}$

cone with DIAMETER of 18 & height of 10

cone with RADIUS of 10 & height of 9

cone with RADIUS of 11 & height of 9

cone with DIAMETER of 20 & height of 12

Step-by-step explanation:

Let $V_{2}. V_{3}. and\ V_{4}.$ be the volume of the cone.

Let d, r and h be the diameter, radius and height of the cone.

Given:

$d_{1} = 20\ and\ h_{1}=12$

$d_{2} = 18\ and\ h_{2}=10$

$r_{3} = 10\ and\ h_{3}=9$

$r_{4} = 11\ and\ h_{14}=9$

Arrange the cones in order from lease volume to greatest volume.

Solution:

The volume of the cone is given below.

$V=\pi r^{2} \frac{h}{3}$ ----------------(1)

where: r is radius of the base of cone.

and h is height of the cone.

The volume of the cone for $d_{1} = 20\ and\ h_{1}=12$

$r_{1} = \frac{d_{1}}{2}$

$r_{1} = \frac{20}{2}=10\ units$

$V_{1}=\pi (r_{1})^{2} \frac{h_{1}}{3}$

$V_{1}=\pi (10)^{2} \frac{12}{3}$

$V_{1}=\pi\times 100\times 4$

$V_{1}=400\pi\ units^{3}$

Similarly, for volume of the cone for $d_{2} = 18\ and\ h_{2}=10$

$r_{2} = \frac{d_{2}}{2}$

$r_{2} = \frac{18}{2}=9\ units$

$V_{2}=\pi (r_{2})^{2} \frac{h_{2}}{3}$

$V_{2}=\pi (9)^{2} \frac{10}{3}$

$V_{2}=\pi\times 81\times \frac{10}{3}$

$V_{2}=\pi\times 27\times 10$

$V_{2}=270\pi\ units^{3}$

Similarly, for volume of the cone for $r_{3} = 10\ and\ h_{3}=9$

$V_{3}=\pi (r_{3})^{2} \frac{h_{3}}{3}$

$V_{3}=\pi (10)^{2} \frac{9}{3}$

$V_{3}=\pi\times 100\times 3$

$V_{3}=\pi\times 300$

$V_{3}=300\pi\ units^{3}$

Similarly, for volume of the cone for $r_{4} = 11\ and\ h_{4}=9$

$V_{4}=\pi (r_{4})^{2} \frac{h_{4}}{3}$

$V_{4}=\pi (11)^{2} \frac{9}{3}$

$V_{4}=\pi\times 121\times 3$

$V_{4}=\pi\times 363$

$V_{4}=363\pi\ units^{3}$

So, the volume of the cone in ascending order.

$V_{2}=270\pi\ units^{3}$

7 0

3 years ago

I need help with this equation. 9q - 14 + 3(q - 8) = 7 I looked it up and the answer was 3.75, however I don't understand how it

coldgirl [10]

Parentheses first

9q-14+3q-3(8)=7
9q-14+3q-24=7

Combine like terms

9q + 3q - 14 - 24 = 7
12q -38=7

add 38 to both sides

12q - 38 + 38 = 7 + 38

12q = 45

divide both sides by 12

q = 45/12
q = 3.75

8 0

3 years ago

1) Which of the following shows the correct steps to find the value of 27 1/3?

sesenic [268]

First of all, we need to know: 3^3 = 3 x 3 x 3 = 9 x 3 = 27

So:

$(27)^{\frac{1}{3}} = (3^3)^{\frac{1}{3}} = (3)^{3\times \frac{1}{3}} = 3^{1} = 3$

So, your answer is D.

4 0

3 years ago

Read 2 more answers

9* – 5( 3*+1) + 54= 0

Kobotan [32]

Answer:

43=0

this should be the answer :)

6 0

3 years ago